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Comment Box for Substitution Method of Integrals
TikZ: Cropping the Bounding BoxHow can I put a coloured outline around fraction lines?TikZ: complicated paths, e.g. for complex integralsRotate a node but not its content: the case of the ellipse decorationContour integralsTikZ/ERD: node (=Entity) label on the insideTikZ: Drawing an arc from an intersection to an intersectionHorner's Method for polynomial long divisionsubstitution in tikz calcTikz: Method to color regions
I want to make a comment box like the image below that adjusts in size as I write up different examples. My MWE is not much
documentclassarticle
usepackageamsmath, mathtools,tikz
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred
x^3+1)^10 textcolorblue3x^2 dx \
&=int textcolorredu^10
textcolorbluedu
endalign*
enddocument
This outputs:

I am trying to recreate with a black box drawn around the orange shaded area.

tikz-pgf
add a comment |
I want to make a comment box like the image below that adjusts in size as I write up different examples. My MWE is not much
documentclassarticle
usepackageamsmath, mathtools,tikz
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred
x^3+1)^10 textcolorblue3x^2 dx \
&=int textcolorredu^10
textcolorbluedu
endalign*
enddocument
This outputs:

I am trying to recreate with a black box drawn around the orange shaded area.

tikz-pgf
add a comment |
I want to make a comment box like the image below that adjusts in size as I write up different examples. My MWE is not much
documentclassarticle
usepackageamsmath, mathtools,tikz
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred
x^3+1)^10 textcolorblue3x^2 dx \
&=int textcolorredu^10
textcolorbluedu
endalign*
enddocument
This outputs:

I am trying to recreate with a black box drawn around the orange shaded area.

tikz-pgf
I want to make a comment box like the image below that adjusts in size as I write up different examples. My MWE is not much
documentclassarticle
usepackageamsmath, mathtools,tikz
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred
x^3+1)^10 textcolorblue3x^2 dx \
&=int textcolorredu^10
textcolorbluedu
endalign*
enddocument
This outputs:

I am trying to recreate with a black box drawn around the orange shaded area.

tikz-pgf
tikz-pgf
asked 11 hours ago
MathScholarMathScholar
1,08529
1,08529
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Using tikzmark, it is not so difficult:
documentclassarticle
usepackageamsmath, mathtools,tikz
usetikzlibrarytikzmark,calc
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred x^3+1)^10 textcolorblue3x^2 dx tikzmarkeqt\
&=int textcolorredu^10textcolorbluedu
endalign*
begintikzpicture[overlay, remember picture]
coordinate (x) at ($(pic cs:eqt)+(1,0)$);
draw (x)--($(x)+(3,0)$);
draw[red] (x) node[above right] Substitution;
draw ($(x)+(3,0)$) node[right,draw,fill=orange!50] %
% Remove `draw' option if you don't want the box
$beginaligned
u&=x^3+1,\
du&=3x^2dx
endaligned$;
endtikzpicture
enddocument

This very nice and creative solution is by @marmot:
documentclass[fleqn]article
usepackageamsmath,tikz
usetikzlibrarytikzmark
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10,mathrmdx
&tikzmarknodeeq1=int (textcolorred x^3+1)^10
textcolorblue3x^2, mathrmdx \
&tikzmarknodeeq2=int textcolorredu^10,textcolorbluemathrmdu
endalign*
begintikzpicture[overlay, remember picture]
path (eq1) -- (eq2) coordinate[midway] (aux);
draw[latex-] (eq2) -- (aux) -- ++ (5,0) node[above left] substitute
node[right,fill=orange!30] %
$beginaligned
u&=x^3+1\
mathrmdu&=3x^2,mathrmdx
endaligned$;
endtikzpicture
enddocument

add a comment |
Without tikz, I define an extensible xmathline, centred on the math axis, which accepts writing above and below it, like xrightarrow, and add a simple colorbox:
documentclass[svgnames]article
usepackageamsmath, mathtools,tikz
usepackagexcolor
usepackagebigstrut
newcommandxmathline[2][]%
ext@arrow 0099xmathlinefill@#1#2%
newcommandxmathlinefill@%
arrowfill@relbarbigstrutrelbarrelbar
makeatother
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred
x^3+1)^10 textcolorblue3x^2 dx
quadxmathlinetextcolorCrimsonsubstitutionquadcolorboxNavajoWhite! 60$beginaligned u & = x^3 + 1 \ du & =3x^2,dx endaligned $ \%
&=int textcolorredu^10
textcolorbluedu
endalign*
enddocument

add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Using tikzmark, it is not so difficult:
documentclassarticle
usepackageamsmath, mathtools,tikz
usetikzlibrarytikzmark,calc
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred x^3+1)^10 textcolorblue3x^2 dx tikzmarkeqt\
&=int textcolorredu^10textcolorbluedu
endalign*
begintikzpicture[overlay, remember picture]
coordinate (x) at ($(pic cs:eqt)+(1,0)$);
draw (x)--($(x)+(3,0)$);
draw[red] (x) node[above right] Substitution;
draw ($(x)+(3,0)$) node[right,draw,fill=orange!50] %
% Remove `draw' option if you don't want the box
$beginaligned
u&=x^3+1,\
du&=3x^2dx
endaligned$;
endtikzpicture
enddocument

This very nice and creative solution is by @marmot:
documentclass[fleqn]article
usepackageamsmath,tikz
usetikzlibrarytikzmark
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10,mathrmdx
&tikzmarknodeeq1=int (textcolorred x^3+1)^10
textcolorblue3x^2, mathrmdx \
&tikzmarknodeeq2=int textcolorredu^10,textcolorbluemathrmdu
endalign*
begintikzpicture[overlay, remember picture]
path (eq1) -- (eq2) coordinate[midway] (aux);
draw[latex-] (eq2) -- (aux) -- ++ (5,0) node[above left] substitute
node[right,fill=orange!30] %
$beginaligned
u&=x^3+1\
mathrmdu&=3x^2,mathrmdx
endaligned$;
endtikzpicture
enddocument

add a comment |
Using tikzmark, it is not so difficult:
documentclassarticle
usepackageamsmath, mathtools,tikz
usetikzlibrarytikzmark,calc
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred x^3+1)^10 textcolorblue3x^2 dx tikzmarkeqt\
&=int textcolorredu^10textcolorbluedu
endalign*
begintikzpicture[overlay, remember picture]
coordinate (x) at ($(pic cs:eqt)+(1,0)$);
draw (x)--($(x)+(3,0)$);
draw[red] (x) node[above right] Substitution;
draw ($(x)+(3,0)$) node[right,draw,fill=orange!50] %
% Remove `draw' option if you don't want the box
$beginaligned
u&=x^3+1,\
du&=3x^2dx
endaligned$;
endtikzpicture
enddocument

This very nice and creative solution is by @marmot:
documentclass[fleqn]article
usepackageamsmath,tikz
usetikzlibrarytikzmark
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10,mathrmdx
&tikzmarknodeeq1=int (textcolorred x^3+1)^10
textcolorblue3x^2, mathrmdx \
&tikzmarknodeeq2=int textcolorredu^10,textcolorbluemathrmdu
endalign*
begintikzpicture[overlay, remember picture]
path (eq1) -- (eq2) coordinate[midway] (aux);
draw[latex-] (eq2) -- (aux) -- ++ (5,0) node[above left] substitute
node[right,fill=orange!30] %
$beginaligned
u&=x^3+1\
mathrmdu&=3x^2,mathrmdx
endaligned$;
endtikzpicture
enddocument

add a comment |
Using tikzmark, it is not so difficult:
documentclassarticle
usepackageamsmath, mathtools,tikz
usetikzlibrarytikzmark,calc
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred x^3+1)^10 textcolorblue3x^2 dx tikzmarkeqt\
&=int textcolorredu^10textcolorbluedu
endalign*
begintikzpicture[overlay, remember picture]
coordinate (x) at ($(pic cs:eqt)+(1,0)$);
draw (x)--($(x)+(3,0)$);
draw[red] (x) node[above right] Substitution;
draw ($(x)+(3,0)$) node[right,draw,fill=orange!50] %
% Remove `draw' option if you don't want the box
$beginaligned
u&=x^3+1,\
du&=3x^2dx
endaligned$;
endtikzpicture
enddocument

This very nice and creative solution is by @marmot:
documentclass[fleqn]article
usepackageamsmath,tikz
usetikzlibrarytikzmark
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10,mathrmdx
&tikzmarknodeeq1=int (textcolorred x^3+1)^10
textcolorblue3x^2, mathrmdx \
&tikzmarknodeeq2=int textcolorredu^10,textcolorbluemathrmdu
endalign*
begintikzpicture[overlay, remember picture]
path (eq1) -- (eq2) coordinate[midway] (aux);
draw[latex-] (eq2) -- (aux) -- ++ (5,0) node[above left] substitute
node[right,fill=orange!30] %
$beginaligned
u&=x^3+1\
mathrmdu&=3x^2,mathrmdx
endaligned$;
endtikzpicture
enddocument

Using tikzmark, it is not so difficult:
documentclassarticle
usepackageamsmath, mathtools,tikz
usetikzlibrarytikzmark,calc
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred x^3+1)^10 textcolorblue3x^2 dx tikzmarkeqt\
&=int textcolorredu^10textcolorbluedu
endalign*
begintikzpicture[overlay, remember picture]
coordinate (x) at ($(pic cs:eqt)+(1,0)$);
draw (x)--($(x)+(3,0)$);
draw[red] (x) node[above right] Substitution;
draw ($(x)+(3,0)$) node[right,draw,fill=orange!50] %
% Remove `draw' option if you don't want the box
$beginaligned
u&=x^3+1,\
du&=3x^2dx
endaligned$;
endtikzpicture
enddocument

This very nice and creative solution is by @marmot:
documentclass[fleqn]article
usepackageamsmath,tikz
usetikzlibrarytikzmark
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10,mathrmdx
&tikzmarknodeeq1=int (textcolorred x^3+1)^10
textcolorblue3x^2, mathrmdx \
&tikzmarknodeeq2=int textcolorredu^10,textcolorbluemathrmdu
endalign*
begintikzpicture[overlay, remember picture]
path (eq1) -- (eq2) coordinate[midway] (aux);
draw[latex-] (eq2) -- (aux) -- ++ (5,0) node[above left] substitute
node[right,fill=orange!30] %
$beginaligned
u&=x^3+1\
mathrmdu&=3x^2,mathrmdx
endaligned$;
endtikzpicture
enddocument

edited 9 hours ago
answered 10 hours ago
JouleVJouleV
6,21121650
6,21121650
add a comment |
add a comment |
Without tikz, I define an extensible xmathline, centred on the math axis, which accepts writing above and below it, like xrightarrow, and add a simple colorbox:
documentclass[svgnames]article
usepackageamsmath, mathtools,tikz
usepackagexcolor
usepackagebigstrut
newcommandxmathline[2][]%
ext@arrow 0099xmathlinefill@#1#2%
newcommandxmathlinefill@%
arrowfill@relbarbigstrutrelbarrelbar
makeatother
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred
x^3+1)^10 textcolorblue3x^2 dx
quadxmathlinetextcolorCrimsonsubstitutionquadcolorboxNavajoWhite! 60$beginaligned u & = x^3 + 1 \ du & =3x^2,dx endaligned $ \%
&=int textcolorredu^10
textcolorbluedu
endalign*
enddocument

add a comment |
Without tikz, I define an extensible xmathline, centred on the math axis, which accepts writing above and below it, like xrightarrow, and add a simple colorbox:
documentclass[svgnames]article
usepackageamsmath, mathtools,tikz
usepackagexcolor
usepackagebigstrut
newcommandxmathline[2][]%
ext@arrow 0099xmathlinefill@#1#2%
newcommandxmathlinefill@%
arrowfill@relbarbigstrutrelbarrelbar
makeatother
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred
x^3+1)^10 textcolorblue3x^2 dx
quadxmathlinetextcolorCrimsonsubstitutionquadcolorboxNavajoWhite! 60$beginaligned u & = x^3 + 1 \ du & =3x^2,dx endaligned $ \%
&=int textcolorredu^10
textcolorbluedu
endalign*
enddocument

add a comment |
Without tikz, I define an extensible xmathline, centred on the math axis, which accepts writing above and below it, like xrightarrow, and add a simple colorbox:
documentclass[svgnames]article
usepackageamsmath, mathtools,tikz
usepackagexcolor
usepackagebigstrut
newcommandxmathline[2][]%
ext@arrow 0099xmathlinefill@#1#2%
newcommandxmathlinefill@%
arrowfill@relbarbigstrutrelbarrelbar
makeatother
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred
x^3+1)^10 textcolorblue3x^2 dx
quadxmathlinetextcolorCrimsonsubstitutionquadcolorboxNavajoWhite! 60$beginaligned u & = x^3 + 1 \ du & =3x^2,dx endaligned $ \%
&=int textcolorredu^10
textcolorbluedu
endalign*
enddocument

Without tikz, I define an extensible xmathline, centred on the math axis, which accepts writing above and below it, like xrightarrow, and add a simple colorbox:
documentclass[svgnames]article
usepackageamsmath, mathtools,tikz
usepackagexcolor
usepackagebigstrut
newcommandxmathline[2][]%
ext@arrow 0099xmathlinefill@#1#2%
newcommandxmathlinefill@%
arrowfill@relbarbigstrutrelbarrelbar
makeatother
begindocument
beginalign*
displaystyleint 3x^2(x^3+1)^10 dx &=int (textcolorred
x^3+1)^10 textcolorblue3x^2 dx
quadxmathlinetextcolorCrimsonsubstitutionquadcolorboxNavajoWhite! 60$beginaligned u & = x^3 + 1 \ du & =3x^2,dx endaligned $ \%
&=int textcolorredu^10
textcolorbluedu
endalign*
enddocument

edited 9 hours ago
answered 10 hours ago
BernardBernard
173k776204
173k776204
add a comment |
add a comment |
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