Why isn't the circumferential light around the M87 black hole's event horizon symmetric? The 2019 Stack Overflow Developer Survey Results Are InGravity on supermassive black hole's event horizonAre gravitons bound by the event horizon?Can the event horizon save conservation laws for black holes?Definition of event horizon - Gravity around blackholesCan a rotating black hole have a donut-shaped event horizon?Why won't the following hypothetical scenario succeed in pulling an object free from a black hole's event horizon?Can rotating black hole have toroidal event horizon with penetrating relativistic jet(s)?Is it possible the space-time manifold itself could stop at a black hole's event horizon?Can anything orbit a black hole with dipping under the event horizon?Does light accelerate inside event horizon

Write faster on AT24C32

What do the Banks children have against barley water?

Are there incongruent pythagorean triangles with the same perimeter and same area?

Did Scotland spend $250,000 for the slogan "Welcome to Scotland"?

Aging parents with no investments

Is a "Democratic" Feudal System Possible?

What is the closest word meaning "respect for time / mindful"

How technical should a Scrum Master be to effectively remove impediments?

Time travel alters history but people keep saying nothing's changed

Why can Shazam fly?

I see my dog run

Why did Acorn's A3000 have red function keys?

How are circuits which use complex ICs normally simulated?

What could be the right powersource for 15 seconds lifespan disposable giant chainsaw?

How to save as into a customized destination on macOS?

Scaling a graph of a circle and the standard parabola in TikZ

Earliest use of the term "Galois extension"?

Identify boardgame from Big movie

Is an up-to-date browser secure on an out-of-date OS?

What are the motivations for publishing new editions of an existing textbook, beyond new discoveries in a field?

Return to UK after being refused entry years previously

Building a conditional check constraint

Pokemon Turn Based battle (Python)

Why was M87 targetted for the Event Horizon Telescope instead of Sagittarius A*?



Why isn't the circumferential light around the M87 black hole's event horizon symmetric?



The 2019 Stack Overflow Developer Survey Results Are InGravity on supermassive black hole's event horizonAre gravitons bound by the event horizon?Can the event horizon save conservation laws for black holes?Definition of event horizon - Gravity around blackholesCan a rotating black hole have a donut-shaped event horizon?Why won't the following hypothetical scenario succeed in pulling an object free from a black hole's event horizon?Can rotating black hole have toroidal event horizon with penetrating relativistic jet(s)?Is it possible the space-time manifold itself could stop at a black hole's event horizon?Can anything orbit a black hole with dipping under the event horizon?Does light accelerate inside event horizon










15












$begingroup$


After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?



enter image description here










share|cite|improve this question











$endgroup$







  • 10




    $begingroup$
    Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
    $endgroup$
    – Paul Sinclair
    6 hours ago
















15












$begingroup$


After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?



enter image description here










share|cite|improve this question











$endgroup$







  • 10




    $begingroup$
    Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
    $endgroup$
    – Paul Sinclair
    6 hours ago














15












15








15


2



$begingroup$


After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?



enter image description here










share|cite|improve this question











$endgroup$




After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?



enter image description here







general-relativity black-holes astronomy event-horizon accretion-disk






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 43 mins ago









Qmechanic

107k121991240




107k121991240










asked 8 hours ago









0x900x90

1,07341533




1,07341533







  • 10




    $begingroup$
    Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
    $endgroup$
    – Paul Sinclair
    6 hours ago













  • 10




    $begingroup$
    Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
    $endgroup$
    – Paul Sinclair
    6 hours ago








10




10




$begingroup$
Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
$endgroup$
– Paul Sinclair
6 hours ago





$begingroup$
Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
$endgroup$
– Paul Sinclair
6 hours ago











4 Answers
4






active

oldest

votes


















15












$begingroup$

This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.



You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:



enter image description here



There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.






share|cite|improve this answer











$endgroup$












  • $begingroup$
    This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
    $endgroup$
    – Rob Jeffries
    1 hour ago



















3












$begingroup$

I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.



enter image description here



Image from BBC News and EHT Collaboration




The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.







share|cite|improve this answer








New contributor




StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$












  • $begingroup$
    I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
    $endgroup$
    – Douglas Held
    3 hours ago










  • $begingroup$
    @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
    $endgroup$
    – StudyStudy
    3 hours ago










  • $begingroup$
    This doesn't address the reason for the asymmetry in the ring at all
    $endgroup$
    – Rob Jeffries
    1 hour ago


















2












$begingroup$

The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.



The pictures below from the fifth event horizon telescope paper makes things clear.



Relative orientation of spin and accretion flow



The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.



The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.






share|cite|improve this answer









$endgroup$




















    0












    $begingroup$

    I found this animated GIF to explain this really well:



    https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif



    Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.






    share|cite|improve this answer








    New contributor




    zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$












    • $begingroup$
      Like Doppler effect?
      $endgroup$
      – 0x90
      1 hour ago










    • $begingroup$
      No - not like doppler effect.
      $endgroup$
      – Rory Alsop
      18 mins ago











    Your Answer





    StackExchange.ifUsing("editor", function ()
    return StackExchange.using("mathjaxEditing", function ()
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    );
    );
    , "mathjax-editing");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "151"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f471753%2fwhy-isnt-the-circumferential-light-around-the-m87-black-holes-event-horizon-sy%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    4 Answers
    4






    active

    oldest

    votes








    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    15












    $begingroup$

    This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.



    You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:



    enter image description here



    There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.






    share|cite|improve this answer











    $endgroup$












    • $begingroup$
      This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
      $endgroup$
      – Rob Jeffries
      1 hour ago
















    15












    $begingroup$

    This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.



    You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:



    enter image description here



    There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.






    share|cite|improve this answer











    $endgroup$












    • $begingroup$
      This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
      $endgroup$
      – Rob Jeffries
      1 hour ago














    15












    15








    15





    $begingroup$

    This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.



    You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:



    enter image description here



    There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.






    share|cite|improve this answer











    $endgroup$



    This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.



    You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:



    enter image description here



    There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.







    share|cite|improve this answer














    share|cite|improve this answer



    share|cite|improve this answer








    edited 8 hours ago

























    answered 8 hours ago









    VoidVoid

    11k11758




    11k11758











    • $begingroup$
      This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
      $endgroup$
      – Rob Jeffries
      1 hour ago

















    • $begingroup$
      This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
      $endgroup$
      – Rob Jeffries
      1 hour ago
















    $begingroup$
    This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
    $endgroup$
    – Rob Jeffries
    1 hour ago





    $begingroup$
    This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
    $endgroup$
    – Rob Jeffries
    1 hour ago












    3












    $begingroup$

    I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.



    enter image description here



    Image from BBC News and EHT Collaboration




    The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.







    share|cite|improve this answer








    New contributor




    StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$












    • $begingroup$
      I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
      $endgroup$
      – Douglas Held
      3 hours ago










    • $begingroup$
      @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
      $endgroup$
      – StudyStudy
      3 hours ago










    • $begingroup$
      This doesn't address the reason for the asymmetry in the ring at all
      $endgroup$
      – Rob Jeffries
      1 hour ago















    3












    $begingroup$

    I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.



    enter image description here



    Image from BBC News and EHT Collaboration




    The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.







    share|cite|improve this answer








    New contributor




    StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$












    • $begingroup$
      I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
      $endgroup$
      – Douglas Held
      3 hours ago










    • $begingroup$
      @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
      $endgroup$
      – StudyStudy
      3 hours ago










    • $begingroup$
      This doesn't address the reason for the asymmetry in the ring at all
      $endgroup$
      – Rob Jeffries
      1 hour ago













    3












    3








    3





    $begingroup$

    I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.



    enter image description here



    Image from BBC News and EHT Collaboration




    The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.







    share|cite|improve this answer








    New contributor




    StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$



    I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.



    enter image description here



    Image from BBC News and EHT Collaboration




    The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.








    share|cite|improve this answer








    New contributor




    StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.









    share|cite|improve this answer



    share|cite|improve this answer






    New contributor




    StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.









    answered 8 hours ago









    StudyStudyStudyStudy

    1397




    1397




    New contributor




    StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





    New contributor





    StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    StudyStudy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.











    • $begingroup$
      I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
      $endgroup$
      – Douglas Held
      3 hours ago










    • $begingroup$
      @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
      $endgroup$
      – StudyStudy
      3 hours ago










    • $begingroup$
      This doesn't address the reason for the asymmetry in the ring at all
      $endgroup$
      – Rob Jeffries
      1 hour ago
















    • $begingroup$
      I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
      $endgroup$
      – Douglas Held
      3 hours ago










    • $begingroup$
      @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
      $endgroup$
      – StudyStudy
      3 hours ago










    • $begingroup$
      This doesn't address the reason for the asymmetry in the ring at all
      $endgroup$
      – Rob Jeffries
      1 hour ago















    $begingroup$
    I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
    $endgroup$
    – Douglas Held
    3 hours ago




    $begingroup$
    I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
    $endgroup$
    – Douglas Held
    3 hours ago












    $begingroup$
    @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
    $endgroup$
    – StudyStudy
    3 hours ago




    $begingroup$
    @DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
    $endgroup$
    – StudyStudy
    3 hours ago












    $begingroup$
    This doesn't address the reason for the asymmetry in the ring at all
    $endgroup$
    – Rob Jeffries
    1 hour ago




    $begingroup$
    This doesn't address the reason for the asymmetry in the ring at all
    $endgroup$
    – Rob Jeffries
    1 hour ago











    2












    $begingroup$

    The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.



    The pictures below from the fifth event horizon telescope paper makes things clear.



    Relative orientation of spin and accretion flow



    The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.



    The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.






    share|cite|improve this answer









    $endgroup$

















      2












      $begingroup$

      The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.



      The pictures below from the fifth event horizon telescope paper makes things clear.



      Relative orientation of spin and accretion flow



      The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.



      The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.






      share|cite|improve this answer









      $endgroup$















        2












        2








        2





        $begingroup$

        The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.



        The pictures below from the fifth event horizon telescope paper makes things clear.



        Relative orientation of spin and accretion flow



        The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.



        The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.






        share|cite|improve this answer









        $endgroup$



        The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.



        The pictures below from the fifth event horizon telescope paper makes things clear.



        Relative orientation of spin and accretion flow



        The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.



        The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 1 hour ago









        Rob JeffriesRob Jeffries

        70.7k7144245




        70.7k7144245





















            0












            $begingroup$

            I found this animated GIF to explain this really well:



            https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif



            Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.






            share|cite|improve this answer








            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$












            • $begingroup$
              Like Doppler effect?
              $endgroup$
              – 0x90
              1 hour ago










            • $begingroup$
              No - not like doppler effect.
              $endgroup$
              – Rory Alsop
              18 mins ago















            0












            $begingroup$

            I found this animated GIF to explain this really well:



            https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif



            Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.






            share|cite|improve this answer








            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$












            • $begingroup$
              Like Doppler effect?
              $endgroup$
              – 0x90
              1 hour ago










            • $begingroup$
              No - not like doppler effect.
              $endgroup$
              – Rory Alsop
              18 mins ago













            0












            0








            0





            $begingroup$

            I found this animated GIF to explain this really well:



            https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif



            Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.






            share|cite|improve this answer








            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$



            I found this animated GIF to explain this really well:



            https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif



            Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.







            share|cite|improve this answer








            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.









            share|cite|improve this answer



            share|cite|improve this answer






            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.









            answered 2 hours ago









            zxbEPREFzxbEPREF

            109




            109




            New contributor




            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            New contributor





            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            zxbEPREF is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.











            • $begingroup$
              Like Doppler effect?
              $endgroup$
              – 0x90
              1 hour ago










            • $begingroup$
              No - not like doppler effect.
              $endgroup$
              – Rory Alsop
              18 mins ago
















            • $begingroup$
              Like Doppler effect?
              $endgroup$
              – 0x90
              1 hour ago










            • $begingroup$
              No - not like doppler effect.
              $endgroup$
              – Rory Alsop
              18 mins ago















            $begingroup$
            Like Doppler effect?
            $endgroup$
            – 0x90
            1 hour ago




            $begingroup$
            Like Doppler effect?
            $endgroup$
            – 0x90
            1 hour ago












            $begingroup$
            No - not like doppler effect.
            $endgroup$
            – Rory Alsop
            18 mins ago




            $begingroup$
            No - not like doppler effect.
            $endgroup$
            – Rory Alsop
            18 mins ago

















            draft saved

            draft discarded
















































            Thanks for contributing an answer to Physics Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f471753%2fwhy-isnt-the-circumferential-light-around-the-m87-black-holes-event-horizon-sy%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Ружовы пелікан Змест Знешні выгляд | Пашырэнне | Асаблівасці біялогіі | Літаратура | НавігацыяДагледжаная версіяправерана1 зменаДагледжаная версіяправерана1 змена/ 22697590 Сістэматыкана ВіківідахВыявына Вікісховішчы174693363011049382

            ValueError: Error when checking input: expected conv2d_13_input to have shape (3, 150, 150) but got array with shape (150, 150, 3)2019 Community Moderator ElectionError when checking : expected dense_1_input to have shape (None, 5) but got array with shape (200, 1)Error 'Expected 2D array, got 1D array instead:'ValueError: Error when checking input: expected lstm_41_input to have 3 dimensions, but got array with shape (40000,100)ValueError: Error when checking target: expected dense_1 to have shape (7,) but got array with shape (1,)ValueError: Error when checking target: expected dense_2 to have shape (1,) but got array with shape (0,)Keras exception: ValueError: Error when checking input: expected conv2d_1_input to have shape (150, 150, 3) but got array with shape (256, 256, 3)Steps taking too long to completewhen checking input: expected dense_1_input to have shape (13328,) but got array with shape (317,)ValueError: Error when checking target: expected dense_3 to have shape (None, 1) but got array with shape (7715, 40000)Keras exception: Error when checking input: expected dense_input to have shape (2,) but got array with shape (1,)

            Illegal assignment from SObject to ContactFetching String, Id from Map - Illegal Assignment Id to Field / ObjectError: Compile Error: Illegal assignment from String to BooleanError: List has no rows for assignment to SObjectError on Test Class - System.QueryException: List has no rows for assignment to SObjectRemote action problemDML requires SObject or SObject list type error“Illegal assignment from List to List”Test Class Fail: Batch Class: System.QueryException: List has no rows for assignment to SObjectMapping to a user'List has no rows for assignment to SObject' Mystery