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Finding the repeating unit of polymerisation given two constituent molecules


Number of hydrogen molecules necessary in acetonitrile/butanediamine polymerisationHow to identify the repeating unit in a polymer?Contact lenses come in two polymer classes, ionic or non-ionic. Whats the significance of having both?Why the backbone of polylactic acid's repeating unit contains only one oxygen?How does cross-linking between polymer chains increase the melting point of the polymer?Polymerisation of methyl methacrylate - can the C=O group get involved?Why must polymers have a repeating unit?Calculating the enthalpy of polymerisation of ethylene given the bond strengthsRepeating unit of poly lactic acid (PLA)Why does the degree of polymerisation remain the same throughout chain-growth polymerisation?













3












$begingroup$



The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?



A. $requireencloseceenclosehorizontalstrike(HNCH2CONHCH2CH2NHCOenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CONHCH2NHCOenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2NHenclosehorizontalstrike)$




I came across this question which requires me to find the structure of the repeating unit of the polymer made by the reaction of two different compounds. However, I am not sure as to which repeating unit would suffice for this particular polymer.



As far as I know, there should be double bonds present at the ends of the repeating unit, so that the pi bond can break and allow the formation of additional bonds, and hence, a chain of molecules. However, using that line of thought I cannot seem to figure out the answer to the question.



I just need a direction, a hint or a clue as to how I should approach problems like such.










share|improve this question











$endgroup$







  • 4




    $begingroup$
    What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
    $endgroup$
    – William R. Ebenezer
    12 hours ago










  • $begingroup$
    Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
    $endgroup$
    – Karsten Theis
    9 hours ago










  • $begingroup$
    "As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
    $endgroup$
    – A.K.
    5 hours ago















3












$begingroup$



The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?



A. $requireencloseceenclosehorizontalstrike(HNCH2CONHCH2CH2NHCOenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CONHCH2NHCOenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2NHenclosehorizontalstrike)$




I came across this question which requires me to find the structure of the repeating unit of the polymer made by the reaction of two different compounds. However, I am not sure as to which repeating unit would suffice for this particular polymer.



As far as I know, there should be double bonds present at the ends of the repeating unit, so that the pi bond can break and allow the formation of additional bonds, and hence, a chain of molecules. However, using that line of thought I cannot seem to figure out the answer to the question.



I just need a direction, a hint or a clue as to how I should approach problems like such.










share|improve this question











$endgroup$







  • 4




    $begingroup$
    What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
    $endgroup$
    – William R. Ebenezer
    12 hours ago










  • $begingroup$
    Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
    $endgroup$
    – Karsten Theis
    9 hours ago










  • $begingroup$
    "As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
    $endgroup$
    – A.K.
    5 hours ago













3












3








3





$begingroup$



The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?



A. $requireencloseceenclosehorizontalstrike(HNCH2CONHCH2CH2NHCOenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CONHCH2NHCOenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2NHenclosehorizontalstrike)$




I came across this question which requires me to find the structure of the repeating unit of the polymer made by the reaction of two different compounds. However, I am not sure as to which repeating unit would suffice for this particular polymer.



As far as I know, there should be double bonds present at the ends of the repeating unit, so that the pi bond can break and allow the formation of additional bonds, and hence, a chain of molecules. However, using that line of thought I cannot seem to figure out the answer to the question.



I just need a direction, a hint or a clue as to how I should approach problems like such.










share|improve this question











$endgroup$





The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?



A. $requireencloseceenclosehorizontalstrike(HNCH2CONHCH2CH2NHCOenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CONHCH2NHCOenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NHCOCH2NHenclosehorizontalstrike)$




I came across this question which requires me to find the structure of the repeating unit of the polymer made by the reaction of two different compounds. However, I am not sure as to which repeating unit would suffice for this particular polymer.



As far as I know, there should be double bonds present at the ends of the repeating unit, so that the pi bond can break and allow the formation of additional bonds, and hence, a chain of molecules. However, using that line of thought I cannot seem to figure out the answer to the question.



I just need a direction, a hint or a clue as to how I should approach problems like such.







polymers






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 9 hours ago









Karsten Theis

4,067542




4,067542










asked 12 hours ago









Selena CarlosSelena Carlos

517




517







  • 4




    $begingroup$
    What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
    $endgroup$
    – William R. Ebenezer
    12 hours ago










  • $begingroup$
    Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
    $endgroup$
    – Karsten Theis
    9 hours ago










  • $begingroup$
    "As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
    $endgroup$
    – A.K.
    5 hours ago












  • 4




    $begingroup$
    What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
    $endgroup$
    – William R. Ebenezer
    12 hours ago










  • $begingroup$
    Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
    $endgroup$
    – Karsten Theis
    9 hours ago










  • $begingroup$
    "As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
    $endgroup$
    – A.K.
    5 hours ago







4




4




$begingroup$
What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
$endgroup$
– William R. Ebenezer
12 hours ago




$begingroup$
What you are mentioning is addition polymerization which malonic acid and ethylenediamine wouldn't dream of doing. Condensation occurs, rather.
$endgroup$
– William R. Ebenezer
12 hours ago












$begingroup$
Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
$endgroup$
– Karsten Theis
9 hours ago




$begingroup$
Draw out the skeletal structures with different colors so you can see how the building blocks combine. If you have monomers A and B, and A can't link with A and B can't link with B, the only polymer you can get is A-B-A-B-A...
$endgroup$
– Karsten Theis
9 hours ago












$begingroup$
"As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
$endgroup$
– A.K.
5 hours ago




$begingroup$
"As far as I know, there should be double bonds present at the ends of the repeating unit"; This is not correct.
$endgroup$
– A.K.
5 hours ago










1 Answer
1






active

oldest

votes


















5












$begingroup$

You are starting out with amino groups on one monomer and carboxylate groups on the other monomer. As William R. Ebenezer states in the comment, these combine via condensation (to form an amide, which is written as -NHCO- or -CONH- in condensed formulas). enter image description here



The linkages in the answer choices between repeating units are not visible until you write another repeating unit next to the ones shown. A. and B. show amide linkages between repeating units, while C. and D. show something else.



Here is the exercise rewritten to emphasize the amide bonds in the repeating units:




The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?



A. $requireencloseceenclosehorizontalstrike(HNCH2CO-NHCH2CH2NH-COenclosehorizontalstrike)$
B. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2COenclosehorizontalstrike)$
C. $ceenclosehorizontalstrike(OCCH2CO-NHCH2NH-COenclosehorizontalstrike)$
D. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2NHenclosehorizontalstrike)$




Now that we emphasized the amide linkages, you can see that the first monomer in A, the second monomer in C and the second monomer in D don't match your starting materials. We can also exclude C. and D. because repeating units are not linked via amides. The answer has to be B.






share|improve this answer











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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    5












    $begingroup$

    You are starting out with amino groups on one monomer and carboxylate groups on the other monomer. As William R. Ebenezer states in the comment, these combine via condensation (to form an amide, which is written as -NHCO- or -CONH- in condensed formulas). enter image description here



    The linkages in the answer choices between repeating units are not visible until you write another repeating unit next to the ones shown. A. and B. show amide linkages between repeating units, while C. and D. show something else.



    Here is the exercise rewritten to emphasize the amide bonds in the repeating units:




    The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?



    A. $requireencloseceenclosehorizontalstrike(HNCH2CO-NHCH2CH2NH-COenclosehorizontalstrike)$
    B. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2COenclosehorizontalstrike)$
    C. $ceenclosehorizontalstrike(OCCH2CO-NHCH2NH-COenclosehorizontalstrike)$
    D. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2NHenclosehorizontalstrike)$




    Now that we emphasized the amide linkages, you can see that the first monomer in A, the second monomer in C and the second monomer in D don't match your starting materials. We can also exclude C. and D. because repeating units are not linked via amides. The answer has to be B.






    share|improve this answer











    $endgroup$

















      5












      $begingroup$

      You are starting out with amino groups on one monomer and carboxylate groups on the other monomer. As William R. Ebenezer states in the comment, these combine via condensation (to form an amide, which is written as -NHCO- or -CONH- in condensed formulas). enter image description here



      The linkages in the answer choices between repeating units are not visible until you write another repeating unit next to the ones shown. A. and B. show amide linkages between repeating units, while C. and D. show something else.



      Here is the exercise rewritten to emphasize the amide bonds in the repeating units:




      The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?



      A. $requireencloseceenclosehorizontalstrike(HNCH2CO-NHCH2CH2NH-COenclosehorizontalstrike)$
      B. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2COenclosehorizontalstrike)$
      C. $ceenclosehorizontalstrike(OCCH2CO-NHCH2NH-COenclosehorizontalstrike)$
      D. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2NHenclosehorizontalstrike)$




      Now that we emphasized the amide linkages, you can see that the first monomer in A, the second monomer in C and the second monomer in D don't match your starting materials. We can also exclude C. and D. because repeating units are not linked via amides. The answer has to be B.






      share|improve this answer











      $endgroup$















        5












        5








        5





        $begingroup$

        You are starting out with amino groups on one monomer and carboxylate groups on the other monomer. As William R. Ebenezer states in the comment, these combine via condensation (to form an amide, which is written as -NHCO- or -CONH- in condensed formulas). enter image description here



        The linkages in the answer choices between repeating units are not visible until you write another repeating unit next to the ones shown. A. and B. show amide linkages between repeating units, while C. and D. show something else.



        Here is the exercise rewritten to emphasize the amide bonds in the repeating units:




        The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?



        A. $requireencloseceenclosehorizontalstrike(HNCH2CO-NHCH2CH2NH-COenclosehorizontalstrike)$
        B. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2COenclosehorizontalstrike)$
        C. $ceenclosehorizontalstrike(OCCH2CO-NHCH2NH-COenclosehorizontalstrike)$
        D. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2NHenclosehorizontalstrike)$




        Now that we emphasized the amide linkages, you can see that the first monomer in A, the second monomer in C and the second monomer in D don't match your starting materials. We can also exclude C. and D. because repeating units are not linked via amides. The answer has to be B.






        share|improve this answer











        $endgroup$



        You are starting out with amino groups on one monomer and carboxylate groups on the other monomer. As William R. Ebenezer states in the comment, these combine via condensation (to form an amide, which is written as -NHCO- or -CONH- in condensed formulas). enter image description here



        The linkages in the answer choices between repeating units are not visible until you write another repeating unit next to the ones shown. A. and B. show amide linkages between repeating units, while C. and D. show something else.



        Here is the exercise rewritten to emphasize the amide bonds in the repeating units:




        The compounds $ceH2NCH2CH2NH2$ and $ceHOOCCH2COOH$ react to form a polymer. What is the structure of the repeating unit of the polymer?



        A. $requireencloseceenclosehorizontalstrike(HNCH2CO-NHCH2CH2NH-COenclosehorizontalstrike)$
        B. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2COenclosehorizontalstrike)$
        C. $ceenclosehorizontalstrike(OCCH2CO-NHCH2NH-COenclosehorizontalstrike)$
        D. $ceenclosehorizontalstrike(HNCH2CH2NH-COCH2NHenclosehorizontalstrike)$




        Now that we emphasized the amide linkages, you can see that the first monomer in A, the second monomer in C and the second monomer in D don't match your starting materials. We can also exclude C. and D. because repeating units are not linked via amides. The answer has to be B.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 8 hours ago

























        answered 9 hours ago









        Karsten TheisKarsten Theis

        4,067542




        4,067542



























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