Why is the expression $(((30 / 2) / 2) / 2)$ same as $30 / 2^3$Order of operations: problem evaluating an expressionExpression with last digits differentWhy exactly does the distributive property work?What values will make this expression realIs $frac5x3$ The Same As $frac53x$?How to evolve an expression with two denominatorsWhy diferent calculators give different values for same expression?magnitude of a root of complex expression plus complex expressionExpression for Change in temperatureWhy do addition and subtraction have the same precedence?
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Why is the expression $(((30 / 2) / 2) / 2)$ same as $30 / 2^3$
Order of operations: problem evaluating an expressionExpression with last digits differentWhy exactly does the distributive property work?What values will make this expression realIs $frac5x3$ The Same As $frac53x$?How to evolve an expression with two denominatorsWhy diferent calculators give different values for same expression?magnitude of a root of complex expression plus complex expressionExpression for Change in temperatureWhy do addition and subtraction have the same precedence?
$begingroup$
Why is the expression $$(((30 / 2) / 2) / 2)$$ same as $$30 / 2^3$$
arithmetic
edited 5 hours ago
Asaf Karagila♦
308k33441774
asked 11 hours ago
Michael MuntaMichael Munta
111111
$endgroup$
add a comment |
$begingroup$
Why is the expression $$(((30 / 2) / 2) / 2)$$ same as $$30 / 2^3$$
arithmetic
edited 5 hours ago
Asaf Karagila♦
308k33441774
asked 11 hours ago
Michael MuntaMichael Munta
111111
$endgroup$
1
$begingroup$
A parenthesis is missing?
$endgroup$
– Dr. Sonnhard Graubner
11 hours ago
$begingroup$
Yes! It is correct
$endgroup$
– HAMIDINE SOUMARE
11 hours ago
$begingroup$
$30/2=15$, $15/2=7.5$, $7.5/2=3.75$. Then $30/2^3=30/8=3.75$.
$endgroup$
– thesmallprint
10 hours ago
add a comment |
$begingroup$
Why is the expression $$(((30 / 2) / 2) / 2)$$ same as $$30 / 2^3$$
arithmetic
edited 5 hours ago
Asaf Karagila♦
308k33441774
asked 11 hours ago
Michael MuntaMichael Munta
111111
$endgroup$
Why is the expression $$(((30 / 2) / 2) / 2)$$ same as $$30 / 2^3$$
arithmetic
arithmetic
edited 5 hours ago
Asaf Karagila♦
308k33441774
asked 11 hours ago
Michael MuntaMichael Munta
111111
edited 5 hours ago
Asaf Karagila♦
308k33441774
asked 11 hours ago
Michael MuntaMichael Munta
111111
edited 5 hours ago
Asaf Karagila♦
308k33441774
edited 5 hours ago
Asaf Karagila♦
308k33441774
edited 5 hours ago
Asaf Karagila♦
308k33441774
308k33441774
asked 11 hours ago
Michael MuntaMichael Munta
111111
asked 11 hours ago
Michael MuntaMichael Munta
111111
asked 11 hours ago
Michael MuntaMichael Munta
111111
111111
1
$begingroup$
A parenthesis is missing?
$endgroup$
– Dr. Sonnhard Graubner
11 hours ago
$begingroup$
Yes! It is correct
$endgroup$
– HAMIDINE SOUMARE
11 hours ago
$begingroup$
$30/2=15$, $15/2=7.5$, $7.5/2=3.75$. Then $30/2^3=30/8=3.75$.
$endgroup$
– thesmallprint
10 hours ago
add a comment |
1
$begingroup$
A parenthesis is missing?
$endgroup$
– Dr. Sonnhard Graubner
11 hours ago
$begingroup$
Yes! It is correct
$endgroup$
– HAMIDINE SOUMARE
11 hours ago
$begingroup$
$30/2=15$, $15/2=7.5$, $7.5/2=3.75$. Then $30/2^3=30/8=3.75$.
$endgroup$
– thesmallprint
10 hours ago
1
1
$begingroup$
A parenthesis is missing?
$endgroup$
– Dr. Sonnhard Graubner
11 hours ago
$begingroup$
A parenthesis is missing?
$endgroup$
– Dr. Sonnhard Graubner
11 hours ago
$begingroup$
Yes! It is correct
$endgroup$
– HAMIDINE SOUMARE
11 hours ago
$begingroup$
Yes! It is correct
$endgroup$
– HAMIDINE SOUMARE
11 hours ago
$begingroup$
$30/2=15$, $15/2=7.5$, $7.5/2=3.75$. Then $30/2^3=30/8=3.75$.
$endgroup$
– thesmallprint
10 hours ago
$begingroup$
$30/2=15$, $15/2=7.5$, $7.5/2=3.75$. Then $30/2^3=30/8=3.75$.
$endgroup$
– thesmallprint
10 hours ago
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Note that
$$beginalign colorblue(30/2)/2 &= frac302times frac12\
&=colorteal frac302^2
endalign.$$
Hence
$$beginalign
(colorblue(30/2)/2)/2 &= colortealleft(frac302^2right)bigg/2\
&= frac302^2times frac12\
&= frac302^3.
endalign$$
answered 11 hours ago
Minus One-TwelfthMinus One-Twelfth
3,328413
$endgroup$
add a comment |
$begingroup$
$$30div2div2div2=frac302div2div2$$
$$=frac302^2div2$$
$$=frac302^3$$
answered 11 hours ago
Peter ForemanPeter Foreman
6,1811317
$endgroup$
2
$begingroup$
Looking at this as a multiplication by a fraction is the only way to prove it?
$endgroup$
– Michael Munta
11 hours ago
add a comment |
$begingroup$
Recall:
$(30/2)=30cdot dfrac12;$
$((30/2)/2)=(30cdot dfrac12)cdot dfrac12;$
$(30/2)/2)/2=$
$((30 cdot dfrac12)cdot dfrac12)cdot dfrac12= 30 cdot (dfrac12)^3= dfrac302^3$
Used: Associative law of multiplication.
answered 10 hours ago
Peter SzilasPeter Szilas
11.8k2822
$endgroup$
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Note that
$$beginalign colorblue(30/2)/2 &= frac302times frac12\
&=colorteal frac302^2
endalign.$$
Hence
$$beginalign
(colorblue(30/2)/2)/2 &= colortealleft(frac302^2right)bigg/2\
&= frac302^2times frac12\
&= frac302^3.
endalign$$
answered 11 hours ago
Minus One-TwelfthMinus One-Twelfth
3,328413
$endgroup$
add a comment |
$begingroup$
Note that
$$beginalign colorblue(30/2)/2 &= frac302times frac12\
&=colorteal frac302^2
endalign.$$
Hence
$$beginalign
(colorblue(30/2)/2)/2 &= colortealleft(frac302^2right)bigg/2\
&= frac302^2times frac12\
&= frac302^3.
endalign$$
answered 11 hours ago
Minus One-TwelfthMinus One-Twelfth
3,328413
$endgroup$
add a comment |
$begingroup$
Note that
$$beginalign colorblue(30/2)/2 &= frac302times frac12\
&=colorteal frac302^2
endalign.$$
Hence
$$beginalign
(colorblue(30/2)/2)/2 &= colortealleft(frac302^2right)bigg/2\
&= frac302^2times frac12\
&= frac302^3.
endalign$$
answered 11 hours ago
Minus One-TwelfthMinus One-Twelfth
3,328413
$endgroup$
Note that
$$beginalign colorblue(30/2)/2 &= frac302times frac12\
&=colorteal frac302^2
endalign.$$
Hence
$$beginalign
(colorblue(30/2)/2)/2 &= colortealleft(frac302^2right)bigg/2\
&= frac302^2times frac12\
&= frac302^3.
endalign$$
answered 11 hours ago
Minus One-TwelfthMinus One-Twelfth
3,328413
edited 11 hours ago
answered 11 hours ago
Minus One-TwelfthMinus One-Twelfth
3,328413
answered 11 hours ago
Minus One-TwelfthMinus One-Twelfth
3,328413
answered 11 hours ago
Minus One-TwelfthMinus One-Twelfth
3,328413
3,328413
add a comment |
add a comment |
$begingroup$
$$30div2div2div2=frac302div2div2$$
$$=frac302^2div2$$
$$=frac302^3$$
answered 11 hours ago
Peter ForemanPeter Foreman
6,1811317
$endgroup$
2
$begingroup$
Looking at this as a multiplication by a fraction is the only way to prove it?
$endgroup$
– Michael Munta
11 hours ago
add a comment |
$begingroup$
$$30div2div2div2=frac302div2div2$$
$$=frac302^2div2$$
$$=frac302^3$$
answered 11 hours ago
Peter ForemanPeter Foreman
6,1811317
$endgroup$
2
$begingroup$
Looking at this as a multiplication by a fraction is the only way to prove it?
$endgroup$
– Michael Munta
11 hours ago
add a comment |
$begingroup$
$$30div2div2div2=frac302div2div2$$
$$=frac302^2div2$$
$$=frac302^3$$
answered 11 hours ago
Peter ForemanPeter Foreman
6,1811317
$endgroup$
$$30div2div2div2=frac302div2div2$$
$$=frac302^2div2$$
$$=frac302^3$$
answered 11 hours ago
Peter ForemanPeter Foreman
6,1811317
answered 11 hours ago
Peter ForemanPeter Foreman
6,1811317
answered 11 hours ago
Peter ForemanPeter Foreman
6,1811317
answered 11 hours ago
Peter ForemanPeter Foreman
6,1811317
6,1811317
2
$begingroup$
Looking at this as a multiplication by a fraction is the only way to prove it?
$endgroup$
– Michael Munta
11 hours ago
add a comment |
2
$begingroup$
Looking at this as a multiplication by a fraction is the only way to prove it?
$endgroup$
– Michael Munta
11 hours ago
2
2
$begingroup$
Looking at this as a multiplication by a fraction is the only way to prove it?
$endgroup$
– Michael Munta
11 hours ago
$begingroup$
Looking at this as a multiplication by a fraction is the only way to prove it?
$endgroup$
– Michael Munta
11 hours ago
add a comment |
$begingroup$
Recall:
$(30/2)=30cdot dfrac12;$
$((30/2)/2)=(30cdot dfrac12)cdot dfrac12;$
$(30/2)/2)/2=$
$((30 cdot dfrac12)cdot dfrac12)cdot dfrac12= 30 cdot (dfrac12)^3= dfrac302^3$
Used: Associative law of multiplication.
answered 10 hours ago
Peter SzilasPeter Szilas
11.8k2822
$endgroup$
add a comment |
$begingroup$
Recall:
$(30/2)=30cdot dfrac12;$
$((30/2)/2)=(30cdot dfrac12)cdot dfrac12;$
$(30/2)/2)/2=$
$((30 cdot dfrac12)cdot dfrac12)cdot dfrac12= 30 cdot (dfrac12)^3= dfrac302^3$
Used: Associative law of multiplication.
answered 10 hours ago
Peter SzilasPeter Szilas
11.8k2822
$endgroup$
add a comment |
$begingroup$
Recall:
$(30/2)=30cdot dfrac12;$
$((30/2)/2)=(30cdot dfrac12)cdot dfrac12;$
$(30/2)/2)/2=$
$((30 cdot dfrac12)cdot dfrac12)cdot dfrac12= 30 cdot (dfrac12)^3= dfrac302^3$
Used: Associative law of multiplication.
answered 10 hours ago
Peter SzilasPeter Szilas
11.8k2822
$endgroup$
Recall:
$(30/2)=30cdot dfrac12;$
$((30/2)/2)=(30cdot dfrac12)cdot dfrac12;$
$(30/2)/2)/2=$
$((30 cdot dfrac12)cdot dfrac12)cdot dfrac12= 30 cdot (dfrac12)^3= dfrac302^3$
Used: Associative law of multiplication.
answered 10 hours ago
Peter SzilasPeter Szilas
11.8k2822
edited 8 hours ago
answered 10 hours ago
Peter SzilasPeter Szilas
11.8k2822
answered 10 hours ago
Peter SzilasPeter Szilas
11.8k2822
answered 10 hours ago
Peter SzilasPeter Szilas
11.8k2822
11.8k2822
add a comment |
add a comment |
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1
$begingroup$
A parenthesis is missing?
$endgroup$
– Dr. Sonnhard Graubner
11 hours ago
$begingroup$
Yes! It is correct
$endgroup$
– HAMIDINE SOUMARE
11 hours ago
$begingroup$
$30/2=15$, $15/2=7.5$, $7.5/2=3.75$. Then $30/2^3=30/8=3.75$.
$endgroup$
– thesmallprint
10 hours ago