How long does it take to type this?Lenient typing testPrint the fingering for the note on a saxophoneFind the Shortest Swype PathOutput optimal trill fingeringsProgram touch-tone instructions for my fingersWhat is the “Ant-Difficulty” of this string?Determine the “Luck” of a stringGenerate Menu Access KeysHow many times should I press this?Should this identifier be suggested?

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Can I interfere when another PC is about to be attacked?

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How long does it take to type this?


Lenient typing testPrint the fingering for the note on a saxophoneFind the Shortest Swype PathOutput optimal trill fingeringsProgram touch-tone instructions for my fingersWhat is the “Ant-Difficulty” of this string?Determine the “Luck” of a stringGenerate Menu Access KeysHow many times should I press this?Should this identifier be suggested?













6












$begingroup$


Introduction



I can type at a moderate pace, using the QWERTY keyboard layout. But if a word like yellowwooddoor has a ton of repeated letters, it takes a bit longer to type it. Even worse is when a word like "jump" has the same finger used for multiple different consecutive letters.



Here's how long it takes me to type letters on each finger (very unscientifically measured):



Columns are Finger name, keystrokes/second, seconds/keystroke, and the keys used by each finger



Typing same letter twice: 
L Pinky 5.2 0.1923076923 1qaz
L Ring 5 0.2 2wsx
L Mid 5.3 0.1886792453 3edc
L Index 5.5 0.1818181818 4rfv5tgb
R Thumb 6.5 0.1538461538 [space]
R Index 6.9 0.1449275362 6yhn7ujm
R Mid 6.3 0.1587301587 8ik,
R Ring 6.2 0.1612903226 9ol.
R Pinky 6.1 0.1639344262 0p;'

Typing different letter on same finger:
L Pinky 4.6 0.2173913043
L Ring 4.6 0.2173913043
L Mid 4.5 0.2222222222
L Index 5.3 0.1886792453
R Index 5.4 0.1851851852
R Mid 5.1 0.1960784314
R Ring 5.2 0.1923076923
R Pinky 5.2 0.1923076923


Same data in CSV format.



It takes



.75 * (first_finger_same_letter_time + second_finger_same_letter_time) / 2


time to switch between two fingers.



Challenge



Given a string as input, how long does it take to type it?



  • The "timer" starts the moment the first key is pressed and ends when the last key is pressed. You are just counting the time between keypresses.

  • This is code-golf. Shortest answer in bytes wins.

  • Submission can be either a complete program or function.

  • Input and output any way you want it, stdin/out, function params, file, doesn't matter.

  • Output should be accurate to at least 3 decimal places (+/- 0.001 for rounding error is fine). Leading 0. for numbers under 1 and trailing newline optional.

  • Input will be a string that contains (lowercase) a-z, 0-9, space, semicolon, comma, period, and apostrophe.

  • I always type spaces with my right thumb.

  • I use the normal touch typing fingers (you can also look at the above table for finger-key mappings).

  • Reference code used to generate test cases

Test cases



(empty string or any one-character string) - 0.000



aa - 0.192



fff - 0.364



fj - 0.123



the quick brown fox jumped over the lazy dog - 5.795



yellowwooddoor - 1.983



orangewooddoor - 1.841



jump on it, jump on it - 2.748



type on it, type on it - 2.549



abcdefghijklmnopqrstuvwxyz01234567890 ;,.' - 5.746



ok, this may not be the most accurate but it's in the ballpark, maybe within 30 percent or so. - 12.138










share|improve this question











$endgroup$







  • 1




    $begingroup$
    Are you sure you use the QUERTY keyboard, not the QWERTY one?
    $endgroup$
    – Embodiment of Ignorance
    9 hours ago










  • $begingroup$
    @EmbodimentofIgnorance oops.
    $endgroup$
    – Daniel M.
    9 hours ago















6












$begingroup$


Introduction



I can type at a moderate pace, using the QWERTY keyboard layout. But if a word like yellowwooddoor has a ton of repeated letters, it takes a bit longer to type it. Even worse is when a word like "jump" has the same finger used for multiple different consecutive letters.



Here's how long it takes me to type letters on each finger (very unscientifically measured):



Columns are Finger name, keystrokes/second, seconds/keystroke, and the keys used by each finger



Typing same letter twice: 
L Pinky 5.2 0.1923076923 1qaz
L Ring 5 0.2 2wsx
L Mid 5.3 0.1886792453 3edc
L Index 5.5 0.1818181818 4rfv5tgb
R Thumb 6.5 0.1538461538 [space]
R Index 6.9 0.1449275362 6yhn7ujm
R Mid 6.3 0.1587301587 8ik,
R Ring 6.2 0.1612903226 9ol.
R Pinky 6.1 0.1639344262 0p;'

Typing different letter on same finger:
L Pinky 4.6 0.2173913043
L Ring 4.6 0.2173913043
L Mid 4.5 0.2222222222
L Index 5.3 0.1886792453
R Index 5.4 0.1851851852
R Mid 5.1 0.1960784314
R Ring 5.2 0.1923076923
R Pinky 5.2 0.1923076923


Same data in CSV format.



It takes



.75 * (first_finger_same_letter_time + second_finger_same_letter_time) / 2


time to switch between two fingers.



Challenge



Given a string as input, how long does it take to type it?



  • The "timer" starts the moment the first key is pressed and ends when the last key is pressed. You are just counting the time between keypresses.

  • This is code-golf. Shortest answer in bytes wins.

  • Submission can be either a complete program or function.

  • Input and output any way you want it, stdin/out, function params, file, doesn't matter.

  • Output should be accurate to at least 3 decimal places (+/- 0.001 for rounding error is fine). Leading 0. for numbers under 1 and trailing newline optional.

  • Input will be a string that contains (lowercase) a-z, 0-9, space, semicolon, comma, period, and apostrophe.

  • I always type spaces with my right thumb.

  • I use the normal touch typing fingers (you can also look at the above table for finger-key mappings).

  • Reference code used to generate test cases

Test cases



(empty string or any one-character string) - 0.000



aa - 0.192



fff - 0.364



fj - 0.123



the quick brown fox jumped over the lazy dog - 5.795



yellowwooddoor - 1.983



orangewooddoor - 1.841



jump on it, jump on it - 2.748



type on it, type on it - 2.549



abcdefghijklmnopqrstuvwxyz01234567890 ;,.' - 5.746



ok, this may not be the most accurate but it's in the ballpark, maybe within 30 percent or so. - 12.138










share|improve this question











$endgroup$







  • 1




    $begingroup$
    Are you sure you use the QUERTY keyboard, not the QWERTY one?
    $endgroup$
    – Embodiment of Ignorance
    9 hours ago










  • $begingroup$
    @EmbodimentofIgnorance oops.
    $endgroup$
    – Daniel M.
    9 hours ago













6












6








6





$begingroup$


Introduction



I can type at a moderate pace, using the QWERTY keyboard layout. But if a word like yellowwooddoor has a ton of repeated letters, it takes a bit longer to type it. Even worse is when a word like "jump" has the same finger used for multiple different consecutive letters.



Here's how long it takes me to type letters on each finger (very unscientifically measured):



Columns are Finger name, keystrokes/second, seconds/keystroke, and the keys used by each finger



Typing same letter twice: 
L Pinky 5.2 0.1923076923 1qaz
L Ring 5 0.2 2wsx
L Mid 5.3 0.1886792453 3edc
L Index 5.5 0.1818181818 4rfv5tgb
R Thumb 6.5 0.1538461538 [space]
R Index 6.9 0.1449275362 6yhn7ujm
R Mid 6.3 0.1587301587 8ik,
R Ring 6.2 0.1612903226 9ol.
R Pinky 6.1 0.1639344262 0p;'

Typing different letter on same finger:
L Pinky 4.6 0.2173913043
L Ring 4.6 0.2173913043
L Mid 4.5 0.2222222222
L Index 5.3 0.1886792453
R Index 5.4 0.1851851852
R Mid 5.1 0.1960784314
R Ring 5.2 0.1923076923
R Pinky 5.2 0.1923076923


Same data in CSV format.



It takes



.75 * (first_finger_same_letter_time + second_finger_same_letter_time) / 2


time to switch between two fingers.



Challenge



Given a string as input, how long does it take to type it?



  • The "timer" starts the moment the first key is pressed and ends when the last key is pressed. You are just counting the time between keypresses.

  • This is code-golf. Shortest answer in bytes wins.

  • Submission can be either a complete program or function.

  • Input and output any way you want it, stdin/out, function params, file, doesn't matter.

  • Output should be accurate to at least 3 decimal places (+/- 0.001 for rounding error is fine). Leading 0. for numbers under 1 and trailing newline optional.

  • Input will be a string that contains (lowercase) a-z, 0-9, space, semicolon, comma, period, and apostrophe.

  • I always type spaces with my right thumb.

  • I use the normal touch typing fingers (you can also look at the above table for finger-key mappings).

  • Reference code used to generate test cases

Test cases



(empty string or any one-character string) - 0.000



aa - 0.192



fff - 0.364



fj - 0.123



the quick brown fox jumped over the lazy dog - 5.795



yellowwooddoor - 1.983



orangewooddoor - 1.841



jump on it, jump on it - 2.748



type on it, type on it - 2.549



abcdefghijklmnopqrstuvwxyz01234567890 ;,.' - 5.746



ok, this may not be the most accurate but it's in the ballpark, maybe within 30 percent or so. - 12.138










share|improve this question











$endgroup$




Introduction



I can type at a moderate pace, using the QWERTY keyboard layout. But if a word like yellowwooddoor has a ton of repeated letters, it takes a bit longer to type it. Even worse is when a word like "jump" has the same finger used for multiple different consecutive letters.



Here's how long it takes me to type letters on each finger (very unscientifically measured):



Columns are Finger name, keystrokes/second, seconds/keystroke, and the keys used by each finger



Typing same letter twice: 
L Pinky 5.2 0.1923076923 1qaz
L Ring 5 0.2 2wsx
L Mid 5.3 0.1886792453 3edc
L Index 5.5 0.1818181818 4rfv5tgb
R Thumb 6.5 0.1538461538 [space]
R Index 6.9 0.1449275362 6yhn7ujm
R Mid 6.3 0.1587301587 8ik,
R Ring 6.2 0.1612903226 9ol.
R Pinky 6.1 0.1639344262 0p;'

Typing different letter on same finger:
L Pinky 4.6 0.2173913043
L Ring 4.6 0.2173913043
L Mid 4.5 0.2222222222
L Index 5.3 0.1886792453
R Index 5.4 0.1851851852
R Mid 5.1 0.1960784314
R Ring 5.2 0.1923076923
R Pinky 5.2 0.1923076923


Same data in CSV format.



It takes



.75 * (first_finger_same_letter_time + second_finger_same_letter_time) / 2


time to switch between two fingers.



Challenge



Given a string as input, how long does it take to type it?



  • The "timer" starts the moment the first key is pressed and ends when the last key is pressed. You are just counting the time between keypresses.

  • This is code-golf. Shortest answer in bytes wins.

  • Submission can be either a complete program or function.

  • Input and output any way you want it, stdin/out, function params, file, doesn't matter.

  • Output should be accurate to at least 3 decimal places (+/- 0.001 for rounding error is fine). Leading 0. for numbers under 1 and trailing newline optional.

  • Input will be a string that contains (lowercase) a-z, 0-9, space, semicolon, comma, period, and apostrophe.

  • I always type spaces with my right thumb.

  • I use the normal touch typing fingers (you can also look at the above table for finger-key mappings).

  • Reference code used to generate test cases

Test cases



(empty string or any one-character string) - 0.000



aa - 0.192



fff - 0.364



fj - 0.123



the quick brown fox jumped over the lazy dog - 5.795



yellowwooddoor - 1.983



orangewooddoor - 1.841



jump on it, jump on it - 2.748



type on it, type on it - 2.549



abcdefghijklmnopqrstuvwxyz01234567890 ;,.' - 5.746



ok, this may not be the most accurate but it's in the ballpark, maybe within 30 percent or so. - 12.138







code-golf string number






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 9 hours ago







Daniel M.

















asked 11 hours ago









Daniel M.Daniel M.

1,99111936




1,99111936







  • 1




    $begingroup$
    Are you sure you use the QUERTY keyboard, not the QWERTY one?
    $endgroup$
    – Embodiment of Ignorance
    9 hours ago










  • $begingroup$
    @EmbodimentofIgnorance oops.
    $endgroup$
    – Daniel M.
    9 hours ago












  • 1




    $begingroup$
    Are you sure you use the QUERTY keyboard, not the QWERTY one?
    $endgroup$
    – Embodiment of Ignorance
    9 hours ago










  • $begingroup$
    @EmbodimentofIgnorance oops.
    $endgroup$
    – Daniel M.
    9 hours ago







1




1




$begingroup$
Are you sure you use the QUERTY keyboard, not the QWERTY one?
$endgroup$
– Embodiment of Ignorance
9 hours ago




$begingroup$
Are you sure you use the QUERTY keyboard, not the QWERTY one?
$endgroup$
– Embodiment of Ignorance
9 hours ago












$begingroup$
@EmbodimentofIgnorance oops.
$endgroup$
– Daniel M.
9 hours ago




$begingroup$
@EmbodimentofIgnorance oops.
$endgroup$
– Daniel M.
9 hours ago










2 Answers
2






active

oldest

votes


















4












$begingroup$


JavaScript (Node.js), 180 bytes





s=>(B=Buffer)(s).map(p=c=>(b='23841410645532207643205431765001333746443'[c*45%91%73%41]*2,t+=1/p?p-b?3/8*(g(b)+g(p)):g(b|c!=s):0,p=b,s=c),t=0,g=x=>10/B('4.2.5-75E6?3>4=4AA')[x])&&t


Try it online!



How?



Storing delays



The helper function $g$ takes an integer $0le x le17$ and returns a delay in seconds.



g = x => 10 / Buffer('4.2.5-75E6?3>4=4AA')[x]


The input $x$ is expected to be either:



  • twice the bin number to get the delay for the same letter

  • twice the bin number + 1 to get the delay for different letters

What is actually stored in the string '4.2.5-75E6?3>4=4AA' is the number of keystrokes per second multiplied by $10$ and converted to ASCII. Conveniently, all resulting characters are printable.



For instance, $5.2$ is stored as chr(52) which is '4'.



Converting a character to a key bin



We use the following hash function to convert an ASCII code $c$ to an index into a lookup table containing the bin numbers in $[0..8]$:



$$i = (((ctimes 45) bmod 91)bmod 73)bmod 41$$



Main loop



The total time $t$ is updated with:



t += // add to t:
1 / p ? // if p is numeric:
p - b ? // if p is not equal to b:
3 / 8 * (g(b) + g(p)) // 0.75 * (g(b) + g(p)) / 2
: // else:
g(b | c != s) // g(b) if c == s or g(b + 1) otherwise
: // else (first iteration):
0 // leave t unchanged


where $p$ is the previous bin and $s$ is the previous character.






share|improve this answer











$endgroup$




















    2












    $begingroup$


    Jelly, 78 bytes



    “bk¶ŀqṣṁq*E’b25+45s2
    Øq;"““;“,.'”Zṙ-ØD;"s2ẎW$€3,4¦ẎœiⱮQḢ€ị¢QƑịZƊQ3.75⁵Ḋ?÷$SµƝS


    Try it online!



    How?



    “...’b25+45s2 - Link 1, keystrokes per 10 seconds: no arguments
    “...’ - base 250 integer = 379310849477441257135820
    b25 - to base 25 = [16,7,7,1,5,1,8,0,10,8,24,9,18,6,17,7,20]
    +45 - add 45 = [61,52,52,46,50,46,53,45,55,53,69,54,63,51,62,52,65]
    s2 - split into twos
    - = [[61,52],[52,46],[50,46],[53,45],[55,53],[69,54],[63,51],[62,52],[65]]
    - For: 0... 1... 2... 3... 4... 6... 8... 9... space

    Øq;"““;“,.'”Zṙ-ØD;"s2ẎW$€3,4¦ẎœiⱮQḢ€ị¢QƑịZƊQ3.75⁵Ḋ?÷$SµƝS - Main Link: list of characters
    µƝ - for each neighbouring pair:
    Øq - qwerty = ["qwertyuiop","asdfghjkl","zxcvbnm"]
    ““;“,.'” - list of lists = ["",";",",.'"]
    " - zip with:
    ; - concatenate = ["qwertyuiop","asdfghjkl;","zxcvbnm,.'"]
    Z - transpose = ["qaz","wsx","edc","rfv","tgb","yhn","ujm","ik,","ol.","p;'"]
    ṙ- - rotate left -1 = ["p;'","qaz","wsx","edc","rfv","tgb","yhn","ujm","ik,","ol."]
    ØD - digits = "0123456789"
    " - zip with:
    ; - concatenate = ["0p;'","1qaz","2wsx","3edc","4rfv","5tgb","6yhn","7ujm","8ik,","9ol."]
    s2 - split into twos = [["0p;'","1qaz"],["2wsx","3edc"],["4rfv","5tgb"],["6yhn","7ujm"],["8ik,","9ol."]]
    ¦ - sparse application...
    3,4 - ...to indices: [3,4]
    $€ - ...do: last two links as a monad for each:
    Ẏ - tighten
    W - wrap in a list = [["0p;'","1qaz"],["2wsx","3edc"],["4rfv5tgb"],["6yhn7ujm"],["8ik,","9ol."]]
    Ẏ - tighten = ["0p;'","1qaz","2wsx","3edc","4rfv5tgb","6yhn7ujm","8ik,","9ol."]
    Q - de-duplicate (the neighbouring letters)
    Ɱ - map with:
    œi - multi-dimensional index-into e.g. "fj" -> [[5,3],[6,7]]
    - (note <space> is not there so yields an empty list)
    Ḣ€ - head of each -> [5,6]
    - (...and the head of an empty list is 0)
    ¢ - call the last Link (1) as a nilad
    ị - index-into -> [[55,53],[69,54]]
    - (...and 0 indexes into the rightmost entry)
    Ɗ - last three links as a monad:
    Ƒ - invariant under?:
    Q - de-duplicate (1 if so, else 0)
    Z - transpose -> [[55,69],[53,54]]
    ị - index-into -> [55,69]
    Q - de-duplicate -> [55,69]
    $ - last two links as a monad:
    ? - if...
    Ḋ - ...condition: dequeue
    3.75 - ...then: 3.75
    ⁵ - ...else: 10 -> 3.75
    ÷ - divide -> [0.06818181818181818,0.05434782608695652]
    S - sum -> 0.12252964426877469
    S - sum





    share|improve this answer











    $endgroup$













      Your Answer





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      2 Answers
      2






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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      4












      $begingroup$


      JavaScript (Node.js), 180 bytes





      s=>(B=Buffer)(s).map(p=c=>(b='23841410645532207643205431765001333746443'[c*45%91%73%41]*2,t+=1/p?p-b?3/8*(g(b)+g(p)):g(b|c!=s):0,p=b,s=c),t=0,g=x=>10/B('4.2.5-75E6?3>4=4AA')[x])&&t


      Try it online!



      How?



      Storing delays



      The helper function $g$ takes an integer $0le x le17$ and returns a delay in seconds.



      g = x => 10 / Buffer('4.2.5-75E6?3>4=4AA')[x]


      The input $x$ is expected to be either:



      • twice the bin number to get the delay for the same letter

      • twice the bin number + 1 to get the delay for different letters

      What is actually stored in the string '4.2.5-75E6?3>4=4AA' is the number of keystrokes per second multiplied by $10$ and converted to ASCII. Conveniently, all resulting characters are printable.



      For instance, $5.2$ is stored as chr(52) which is '4'.



      Converting a character to a key bin



      We use the following hash function to convert an ASCII code $c$ to an index into a lookup table containing the bin numbers in $[0..8]$:



      $$i = (((ctimes 45) bmod 91)bmod 73)bmod 41$$



      Main loop



      The total time $t$ is updated with:



      t += // add to t:
      1 / p ? // if p is numeric:
      p - b ? // if p is not equal to b:
      3 / 8 * (g(b) + g(p)) // 0.75 * (g(b) + g(p)) / 2
      : // else:
      g(b | c != s) // g(b) if c == s or g(b + 1) otherwise
      : // else (first iteration):
      0 // leave t unchanged


      where $p$ is the previous bin and $s$ is the previous character.






      share|improve this answer











      $endgroup$

















        4












        $begingroup$


        JavaScript (Node.js), 180 bytes





        s=>(B=Buffer)(s).map(p=c=>(b='23841410645532207643205431765001333746443'[c*45%91%73%41]*2,t+=1/p?p-b?3/8*(g(b)+g(p)):g(b|c!=s):0,p=b,s=c),t=0,g=x=>10/B('4.2.5-75E6?3>4=4AA')[x])&&t


        Try it online!



        How?



        Storing delays



        The helper function $g$ takes an integer $0le x le17$ and returns a delay in seconds.



        g = x => 10 / Buffer('4.2.5-75E6?3>4=4AA')[x]


        The input $x$ is expected to be either:



        • twice the bin number to get the delay for the same letter

        • twice the bin number + 1 to get the delay for different letters

        What is actually stored in the string '4.2.5-75E6?3>4=4AA' is the number of keystrokes per second multiplied by $10$ and converted to ASCII. Conveniently, all resulting characters are printable.



        For instance, $5.2$ is stored as chr(52) which is '4'.



        Converting a character to a key bin



        We use the following hash function to convert an ASCII code $c$ to an index into a lookup table containing the bin numbers in $[0..8]$:



        $$i = (((ctimes 45) bmod 91)bmod 73)bmod 41$$



        Main loop



        The total time $t$ is updated with:



        t += // add to t:
        1 / p ? // if p is numeric:
        p - b ? // if p is not equal to b:
        3 / 8 * (g(b) + g(p)) // 0.75 * (g(b) + g(p)) / 2
        : // else:
        g(b | c != s) // g(b) if c == s or g(b + 1) otherwise
        : // else (first iteration):
        0 // leave t unchanged


        where $p$ is the previous bin and $s$ is the previous character.






        share|improve this answer











        $endgroup$















          4












          4








          4





          $begingroup$


          JavaScript (Node.js), 180 bytes





          s=>(B=Buffer)(s).map(p=c=>(b='23841410645532207643205431765001333746443'[c*45%91%73%41]*2,t+=1/p?p-b?3/8*(g(b)+g(p)):g(b|c!=s):0,p=b,s=c),t=0,g=x=>10/B('4.2.5-75E6?3>4=4AA')[x])&&t


          Try it online!



          How?



          Storing delays



          The helper function $g$ takes an integer $0le x le17$ and returns a delay in seconds.



          g = x => 10 / Buffer('4.2.5-75E6?3>4=4AA')[x]


          The input $x$ is expected to be either:



          • twice the bin number to get the delay for the same letter

          • twice the bin number + 1 to get the delay for different letters

          What is actually stored in the string '4.2.5-75E6?3>4=4AA' is the number of keystrokes per second multiplied by $10$ and converted to ASCII. Conveniently, all resulting characters are printable.



          For instance, $5.2$ is stored as chr(52) which is '4'.



          Converting a character to a key bin



          We use the following hash function to convert an ASCII code $c$ to an index into a lookup table containing the bin numbers in $[0..8]$:



          $$i = (((ctimes 45) bmod 91)bmod 73)bmod 41$$



          Main loop



          The total time $t$ is updated with:



          t += // add to t:
          1 / p ? // if p is numeric:
          p - b ? // if p is not equal to b:
          3 / 8 * (g(b) + g(p)) // 0.75 * (g(b) + g(p)) / 2
          : // else:
          g(b | c != s) // g(b) if c == s or g(b + 1) otherwise
          : // else (first iteration):
          0 // leave t unchanged


          where $p$ is the previous bin and $s$ is the previous character.






          share|improve this answer











          $endgroup$




          JavaScript (Node.js), 180 bytes





          s=>(B=Buffer)(s).map(p=c=>(b='23841410645532207643205431765001333746443'[c*45%91%73%41]*2,t+=1/p?p-b?3/8*(g(b)+g(p)):g(b|c!=s):0,p=b,s=c),t=0,g=x=>10/B('4.2.5-75E6?3>4=4AA')[x])&&t


          Try it online!



          How?



          Storing delays



          The helper function $g$ takes an integer $0le x le17$ and returns a delay in seconds.



          g = x => 10 / Buffer('4.2.5-75E6?3>4=4AA')[x]


          The input $x$ is expected to be either:



          • twice the bin number to get the delay for the same letter

          • twice the bin number + 1 to get the delay for different letters

          What is actually stored in the string '4.2.5-75E6?3>4=4AA' is the number of keystrokes per second multiplied by $10$ and converted to ASCII. Conveniently, all resulting characters are printable.



          For instance, $5.2$ is stored as chr(52) which is '4'.



          Converting a character to a key bin



          We use the following hash function to convert an ASCII code $c$ to an index into a lookup table containing the bin numbers in $[0..8]$:



          $$i = (((ctimes 45) bmod 91)bmod 73)bmod 41$$



          Main loop



          The total time $t$ is updated with:



          t += // add to t:
          1 / p ? // if p is numeric:
          p - b ? // if p is not equal to b:
          3 / 8 * (g(b) + g(p)) // 0.75 * (g(b) + g(p)) / 2
          : // else:
          g(b | c != s) // g(b) if c == s or g(b + 1) otherwise
          : // else (first iteration):
          0 // leave t unchanged


          where $p$ is the previous bin and $s$ is the previous character.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 8 hours ago

























          answered 9 hours ago









          ArnauldArnauld

          80.5k797333




          80.5k797333





















              2












              $begingroup$


              Jelly, 78 bytes



              “bk¶ŀqṣṁq*E’b25+45s2
              Øq;"““;“,.'”Zṙ-ØD;"s2ẎW$€3,4¦ẎœiⱮQḢ€ị¢QƑịZƊQ3.75⁵Ḋ?÷$SµƝS


              Try it online!



              How?



              “...’b25+45s2 - Link 1, keystrokes per 10 seconds: no arguments
              “...’ - base 250 integer = 379310849477441257135820
              b25 - to base 25 = [16,7,7,1,5,1,8,0,10,8,24,9,18,6,17,7,20]
              +45 - add 45 = [61,52,52,46,50,46,53,45,55,53,69,54,63,51,62,52,65]
              s2 - split into twos
              - = [[61,52],[52,46],[50,46],[53,45],[55,53],[69,54],[63,51],[62,52],[65]]
              - For: 0... 1... 2... 3... 4... 6... 8... 9... space

              Øq;"““;“,.'”Zṙ-ØD;"s2ẎW$€3,4¦ẎœiⱮQḢ€ị¢QƑịZƊQ3.75⁵Ḋ?÷$SµƝS - Main Link: list of characters
              µƝ - for each neighbouring pair:
              Øq - qwerty = ["qwertyuiop","asdfghjkl","zxcvbnm"]
              ““;“,.'” - list of lists = ["",";",",.'"]
              " - zip with:
              ; - concatenate = ["qwertyuiop","asdfghjkl;","zxcvbnm,.'"]
              Z - transpose = ["qaz","wsx","edc","rfv","tgb","yhn","ujm","ik,","ol.","p;'"]
              ṙ- - rotate left -1 = ["p;'","qaz","wsx","edc","rfv","tgb","yhn","ujm","ik,","ol."]
              ØD - digits = "0123456789"
              " - zip with:
              ; - concatenate = ["0p;'","1qaz","2wsx","3edc","4rfv","5tgb","6yhn","7ujm","8ik,","9ol."]
              s2 - split into twos = [["0p;'","1qaz"],["2wsx","3edc"],["4rfv","5tgb"],["6yhn","7ujm"],["8ik,","9ol."]]
              ¦ - sparse application...
              3,4 - ...to indices: [3,4]
              $€ - ...do: last two links as a monad for each:
              Ẏ - tighten
              W - wrap in a list = [["0p;'","1qaz"],["2wsx","3edc"],["4rfv5tgb"],["6yhn7ujm"],["8ik,","9ol."]]
              Ẏ - tighten = ["0p;'","1qaz","2wsx","3edc","4rfv5tgb","6yhn7ujm","8ik,","9ol."]
              Q - de-duplicate (the neighbouring letters)
              Ɱ - map with:
              œi - multi-dimensional index-into e.g. "fj" -> [[5,3],[6,7]]
              - (note <space> is not there so yields an empty list)
              Ḣ€ - head of each -> [5,6]
              - (...and the head of an empty list is 0)
              ¢ - call the last Link (1) as a nilad
              ị - index-into -> [[55,53],[69,54]]
              - (...and 0 indexes into the rightmost entry)
              Ɗ - last three links as a monad:
              Ƒ - invariant under?:
              Q - de-duplicate (1 if so, else 0)
              Z - transpose -> [[55,69],[53,54]]
              ị - index-into -> [55,69]
              Q - de-duplicate -> [55,69]
              $ - last two links as a monad:
              ? - if...
              Ḋ - ...condition: dequeue
              3.75 - ...then: 3.75
              ⁵ - ...else: 10 -> 3.75
              ÷ - divide -> [0.06818181818181818,0.05434782608695652]
              S - sum -> 0.12252964426877469
              S - sum





              share|improve this answer











              $endgroup$

















                2












                $begingroup$


                Jelly, 78 bytes



                “bk¶ŀqṣṁq*E’b25+45s2
                Øq;"““;“,.'”Zṙ-ØD;"s2ẎW$€3,4¦ẎœiⱮQḢ€ị¢QƑịZƊQ3.75⁵Ḋ?÷$SµƝS


                Try it online!



                How?



                “...’b25+45s2 - Link 1, keystrokes per 10 seconds: no arguments
                “...’ - base 250 integer = 379310849477441257135820
                b25 - to base 25 = [16,7,7,1,5,1,8,0,10,8,24,9,18,6,17,7,20]
                +45 - add 45 = [61,52,52,46,50,46,53,45,55,53,69,54,63,51,62,52,65]
                s2 - split into twos
                - = [[61,52],[52,46],[50,46],[53,45],[55,53],[69,54],[63,51],[62,52],[65]]
                - For: 0... 1... 2... 3... 4... 6... 8... 9... space

                Øq;"““;“,.'”Zṙ-ØD;"s2ẎW$€3,4¦ẎœiⱮQḢ€ị¢QƑịZƊQ3.75⁵Ḋ?÷$SµƝS - Main Link: list of characters
                µƝ - for each neighbouring pair:
                Øq - qwerty = ["qwertyuiop","asdfghjkl","zxcvbnm"]
                ““;“,.'” - list of lists = ["",";",",.'"]
                " - zip with:
                ; - concatenate = ["qwertyuiop","asdfghjkl;","zxcvbnm,.'"]
                Z - transpose = ["qaz","wsx","edc","rfv","tgb","yhn","ujm","ik,","ol.","p;'"]
                ṙ- - rotate left -1 = ["p;'","qaz","wsx","edc","rfv","tgb","yhn","ujm","ik,","ol."]
                ØD - digits = "0123456789"
                " - zip with:
                ; - concatenate = ["0p;'","1qaz","2wsx","3edc","4rfv","5tgb","6yhn","7ujm","8ik,","9ol."]
                s2 - split into twos = [["0p;'","1qaz"],["2wsx","3edc"],["4rfv","5tgb"],["6yhn","7ujm"],["8ik,","9ol."]]
                ¦ - sparse application...
                3,4 - ...to indices: [3,4]
                $€ - ...do: last two links as a monad for each:
                Ẏ - tighten
                W - wrap in a list = [["0p;'","1qaz"],["2wsx","3edc"],["4rfv5tgb"],["6yhn7ujm"],["8ik,","9ol."]]
                Ẏ - tighten = ["0p;'","1qaz","2wsx","3edc","4rfv5tgb","6yhn7ujm","8ik,","9ol."]
                Q - de-duplicate (the neighbouring letters)
                Ɱ - map with:
                œi - multi-dimensional index-into e.g. "fj" -> [[5,3],[6,7]]
                - (note <space> is not there so yields an empty list)
                Ḣ€ - head of each -> [5,6]
                - (...and the head of an empty list is 0)
                ¢ - call the last Link (1) as a nilad
                ị - index-into -> [[55,53],[69,54]]
                - (...and 0 indexes into the rightmost entry)
                Ɗ - last three links as a monad:
                Ƒ - invariant under?:
                Q - de-duplicate (1 if so, else 0)
                Z - transpose -> [[55,69],[53,54]]
                ị - index-into -> [55,69]
                Q - de-duplicate -> [55,69]
                $ - last two links as a monad:
                ? - if...
                Ḋ - ...condition: dequeue
                3.75 - ...then: 3.75
                ⁵ - ...else: 10 -> 3.75
                ÷ - divide -> [0.06818181818181818,0.05434782608695652]
                S - sum -> 0.12252964426877469
                S - sum





                share|improve this answer











                $endgroup$















                  2












                  2








                  2





                  $begingroup$


                  Jelly, 78 bytes



                  “bk¶ŀqṣṁq*E’b25+45s2
                  Øq;"““;“,.'”Zṙ-ØD;"s2ẎW$€3,4¦ẎœiⱮQḢ€ị¢QƑịZƊQ3.75⁵Ḋ?÷$SµƝS


                  Try it online!



                  How?



                  “...’b25+45s2 - Link 1, keystrokes per 10 seconds: no arguments
                  “...’ - base 250 integer = 379310849477441257135820
                  b25 - to base 25 = [16,7,7,1,5,1,8,0,10,8,24,9,18,6,17,7,20]
                  +45 - add 45 = [61,52,52,46,50,46,53,45,55,53,69,54,63,51,62,52,65]
                  s2 - split into twos
                  - = [[61,52],[52,46],[50,46],[53,45],[55,53],[69,54],[63,51],[62,52],[65]]
                  - For: 0... 1... 2... 3... 4... 6... 8... 9... space

                  Øq;"““;“,.'”Zṙ-ØD;"s2ẎW$€3,4¦ẎœiⱮQḢ€ị¢QƑịZƊQ3.75⁵Ḋ?÷$SµƝS - Main Link: list of characters
                  µƝ - for each neighbouring pair:
                  Øq - qwerty = ["qwertyuiop","asdfghjkl","zxcvbnm"]
                  ““;“,.'” - list of lists = ["",";",",.'"]
                  " - zip with:
                  ; - concatenate = ["qwertyuiop","asdfghjkl;","zxcvbnm,.'"]
                  Z - transpose = ["qaz","wsx","edc","rfv","tgb","yhn","ujm","ik,","ol.","p;'"]
                  ṙ- - rotate left -1 = ["p;'","qaz","wsx","edc","rfv","tgb","yhn","ujm","ik,","ol."]
                  ØD - digits = "0123456789"
                  " - zip with:
                  ; - concatenate = ["0p;'","1qaz","2wsx","3edc","4rfv","5tgb","6yhn","7ujm","8ik,","9ol."]
                  s2 - split into twos = [["0p;'","1qaz"],["2wsx","3edc"],["4rfv","5tgb"],["6yhn","7ujm"],["8ik,","9ol."]]
                  ¦ - sparse application...
                  3,4 - ...to indices: [3,4]
                  $€ - ...do: last two links as a monad for each:
                  Ẏ - tighten
                  W - wrap in a list = [["0p;'","1qaz"],["2wsx","3edc"],["4rfv5tgb"],["6yhn7ujm"],["8ik,","9ol."]]
                  Ẏ - tighten = ["0p;'","1qaz","2wsx","3edc","4rfv5tgb","6yhn7ujm","8ik,","9ol."]
                  Q - de-duplicate (the neighbouring letters)
                  Ɱ - map with:
                  œi - multi-dimensional index-into e.g. "fj" -> [[5,3],[6,7]]
                  - (note <space> is not there so yields an empty list)
                  Ḣ€ - head of each -> [5,6]
                  - (...and the head of an empty list is 0)
                  ¢ - call the last Link (1) as a nilad
                  ị - index-into -> [[55,53],[69,54]]
                  - (...and 0 indexes into the rightmost entry)
                  Ɗ - last three links as a monad:
                  Ƒ - invariant under?:
                  Q - de-duplicate (1 if so, else 0)
                  Z - transpose -> [[55,69],[53,54]]
                  ị - index-into -> [55,69]
                  Q - de-duplicate -> [55,69]
                  $ - last two links as a monad:
                  ? - if...
                  Ḋ - ...condition: dequeue
                  3.75 - ...then: 3.75
                  ⁵ - ...else: 10 -> 3.75
                  ÷ - divide -> [0.06818181818181818,0.05434782608695652]
                  S - sum -> 0.12252964426877469
                  S - sum





                  share|improve this answer











                  $endgroup$




                  Jelly, 78 bytes



                  “bk¶ŀqṣṁq*E’b25+45s2
                  Øq;"““;“,.'”Zṙ-ØD;"s2ẎW$€3,4¦ẎœiⱮQḢ€ị¢QƑịZƊQ3.75⁵Ḋ?÷$SµƝS


                  Try it online!



                  How?



                  “...’b25+45s2 - Link 1, keystrokes per 10 seconds: no arguments
                  “...’ - base 250 integer = 379310849477441257135820
                  b25 - to base 25 = [16,7,7,1,5,1,8,0,10,8,24,9,18,6,17,7,20]
                  +45 - add 45 = [61,52,52,46,50,46,53,45,55,53,69,54,63,51,62,52,65]
                  s2 - split into twos
                  - = [[61,52],[52,46],[50,46],[53,45],[55,53],[69,54],[63,51],[62,52],[65]]
                  - For: 0... 1... 2... 3... 4... 6... 8... 9... space

                  Øq;"““;“,.'”Zṙ-ØD;"s2ẎW$€3,4¦ẎœiⱮQḢ€ị¢QƑịZƊQ3.75⁵Ḋ?÷$SµƝS - Main Link: list of characters
                  µƝ - for each neighbouring pair:
                  Øq - qwerty = ["qwertyuiop","asdfghjkl","zxcvbnm"]
                  ““;“,.'” - list of lists = ["",";",",.'"]
                  " - zip with:
                  ; - concatenate = ["qwertyuiop","asdfghjkl;","zxcvbnm,.'"]
                  Z - transpose = ["qaz","wsx","edc","rfv","tgb","yhn","ujm","ik,","ol.","p;'"]
                  ṙ- - rotate left -1 = ["p;'","qaz","wsx","edc","rfv","tgb","yhn","ujm","ik,","ol."]
                  ØD - digits = "0123456789"
                  " - zip with:
                  ; - concatenate = ["0p;'","1qaz","2wsx","3edc","4rfv","5tgb","6yhn","7ujm","8ik,","9ol."]
                  s2 - split into twos = [["0p;'","1qaz"],["2wsx","3edc"],["4rfv","5tgb"],["6yhn","7ujm"],["8ik,","9ol."]]
                  ¦ - sparse application...
                  3,4 - ...to indices: [3,4]
                  $€ - ...do: last two links as a monad for each:
                  Ẏ - tighten
                  W - wrap in a list = [["0p;'","1qaz"],["2wsx","3edc"],["4rfv5tgb"],["6yhn7ujm"],["8ik,","9ol."]]
                  Ẏ - tighten = ["0p;'","1qaz","2wsx","3edc","4rfv5tgb","6yhn7ujm","8ik,","9ol."]
                  Q - de-duplicate (the neighbouring letters)
                  Ɱ - map with:
                  œi - multi-dimensional index-into e.g. "fj" -> [[5,3],[6,7]]
                  - (note <space> is not there so yields an empty list)
                  Ḣ€ - head of each -> [5,6]
                  - (...and the head of an empty list is 0)
                  ¢ - call the last Link (1) as a nilad
                  ị - index-into -> [[55,53],[69,54]]
                  - (...and 0 indexes into the rightmost entry)
                  Ɗ - last three links as a monad:
                  Ƒ - invariant under?:
                  Q - de-duplicate (1 if so, else 0)
                  Z - transpose -> [[55,69],[53,54]]
                  ị - index-into -> [55,69]
                  Q - de-duplicate -> [55,69]
                  $ - last two links as a monad:
                  ? - if...
                  Ḋ - ...condition: dequeue
                  3.75 - ...then: 3.75
                  ⁵ - ...else: 10 -> 3.75
                  ÷ - divide -> [0.06818181818181818,0.05434782608695652]
                  S - sum -> 0.12252964426877469
                  S - sum






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 5 hours ago

























                  answered 5 hours ago









                  Jonathan AllanJonathan Allan

                  53.8k535173




                  53.8k535173



























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                      ValueError: Expected n_neighbors <= n_samples, but n_samples = 1, n_neighbors = 6 (SMOTE) The 2019 Stack Overflow Developer Survey Results Are InCan SMOTE be applied over sequence of words (sentences)?ValueError when doing validation with random forestsSMOTE and multi class oversamplingLogic behind SMOTE-NC?ValueError: Error when checking target: expected dense_1 to have shape (7,) but got array with shape (1,)SmoteBoost: Should SMOTE be ran individually for each iteration/tree in the boosting?solving multi-class imbalance classification using smote and OSSUsing SMOTE for Synthetic Data generation to improve performance on unbalanced dataproblem of entry format for a simple model in KerasSVM SMOTE fit_resample() function runs forever with no result