100 items 100 baskets divisor association analysis problem The 2019 Stack Overflow Developer Survey Results Are InHow does SQL Server Analysis Services compare to R?Question about (Python/Orange) Apriori associative algorithmCalculate the overall accuracy of mined rules using apiriori algorithmDoes the count of items in a transaction matter to apriori?Data sources problemRecognize a grammar in a sequence of fuzzy tokensItems in a transaction must be unique but got WrappedArrayWhat is confidence reflexivity in association rules?Mining Association rules from a data warehouse and a transactional database
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100 items 100 baskets divisor association analysis problem
The 2019 Stack Overflow Developer Survey Results Are InHow does SQL Server Analysis Services compare to R?Question about (Python/Orange) Apriori associative algorithmCalculate the overall accuracy of mined rules using apiriori algorithmDoes the count of items in a transaction matter to apriori?Data sources problemRecognize a grammar in a sequence of fuzzy tokensItems in a transaction must be unique but got WrappedArrayWhat is confidence reflexivity in association rules?Mining Association rules from a data warehouse and a transactional database
$begingroup$
I have the following exercise question:
Suppose there are 100 items, numbered 1 to 100, and also 100 baskets, also numbered 1 to 100. Item i is in basket b if and only if i divides b with no remainder. Thus, item 1 is in all the baskets, item 2 is in all fifty of the even-numbered baskets, etc. for example Basket 12 consists of items 1, 2, 3, 4, 6, 12
Given this, I'm trying to solve the following 3 questions:
(a) If the support threshold is 5, which items are frequent?
(b) what is the confidence of the following association rules?
(1) 5, 7 → 2.
(2) 2, 3, 4→ 5.
which way I should be approaching these types of questions?
data-mining market-basket-analysis
asked Jan 28 at 23:49
deshawndeshawn
23
$endgroup$
add a comment |
$begingroup$
I have the following exercise question:
Suppose there are 100 items, numbered 1 to 100, and also 100 baskets, also numbered 1 to 100. Item i is in basket b if and only if i divides b with no remainder. Thus, item 1 is in all the baskets, item 2 is in all fifty of the even-numbered baskets, etc. for example Basket 12 consists of items 1, 2, 3, 4, 6, 12
Given this, I'm trying to solve the following 3 questions:
(a) If the support threshold is 5, which items are frequent?
(b) what is the confidence of the following association rules?
(1) 5, 7 → 2.
(2) 2, 3, 4→ 5.
which way I should be approaching these types of questions?
data-mining market-basket-analysis
asked Jan 28 at 23:49
deshawndeshawn
23
$endgroup$
$begingroup$
Isn't this best suited for Mathematics SE or maybe Cross-validated SE ? I fail to see how this is related to Data Science, this is rather related to pure probability/set math and how it fit data-mining itself. Note: Although this is an important concept for the tags referred this is not applied but rather pure math.
$endgroup$
– Pedro Henrique Monforte
9 hours ago
add a comment |
$begingroup$
I have the following exercise question:
Suppose there are 100 items, numbered 1 to 100, and also 100 baskets, also numbered 1 to 100. Item i is in basket b if and only if i divides b with no remainder. Thus, item 1 is in all the baskets, item 2 is in all fifty of the even-numbered baskets, etc. for example Basket 12 consists of items 1, 2, 3, 4, 6, 12
Given this, I'm trying to solve the following 3 questions:
(a) If the support threshold is 5, which items are frequent?
(b) what is the confidence of the following association rules?
(1) 5, 7 → 2.
(2) 2, 3, 4→ 5.
which way I should be approaching these types of questions?
data-mining market-basket-analysis
asked Jan 28 at 23:49
deshawndeshawn
23
$endgroup$
I have the following exercise question:
Suppose there are 100 items, numbered 1 to 100, and also 100 baskets, also numbered 1 to 100. Item i is in basket b if and only if i divides b with no remainder. Thus, item 1 is in all the baskets, item 2 is in all fifty of the even-numbered baskets, etc. for example Basket 12 consists of items 1, 2, 3, 4, 6, 12
Given this, I'm trying to solve the following 3 questions:
(a) If the support threshold is 5, which items are frequent?
(b) what is the confidence of the following association rules?
(1) 5, 7 → 2.
(2) 2, 3, 4→ 5.
which way I should be approaching these types of questions?
data-mining market-basket-analysis
data-mining market-basket-analysis
asked Jan 28 at 23:49
deshawndeshawn
23
asked Jan 28 at 23:49
deshawndeshawn
23
edited Jan 31 at 23:34
deshawn
asked Jan 28 at 23:49
deshawndeshawn
23
asked Jan 28 at 23:49
deshawndeshawn
23
asked Jan 28 at 23:49
deshawndeshawn
23
23
$begingroup$
Isn't this best suited for Mathematics SE or maybe Cross-validated SE ? I fail to see how this is related to Data Science, this is rather related to pure probability/set math and how it fit data-mining itself. Note: Although this is an important concept for the tags referred this is not applied but rather pure math.
$endgroup$
– Pedro Henrique Monforte
9 hours ago
add a comment |
$begingroup$
Isn't this best suited for Mathematics SE or maybe Cross-validated SE ? I fail to see how this is related to Data Science, this is rather related to pure probability/set math and how it fit data-mining itself. Note: Although this is an important concept for the tags referred this is not applied but rather pure math.
$endgroup$
– Pedro Henrique Monforte
9 hours ago
$begingroup$
Isn't this best suited for Mathematics SE or maybe Cross-validated SE ? I fail to see how this is related to Data Science, this is rather related to pure probability/set math and how it fit data-mining itself. Note: Although this is an important concept for the tags referred this is not applied but rather pure math.
$endgroup$
– Pedro Henrique Monforte
9 hours ago
$begingroup$
Isn't this best suited for Mathematics SE or maybe Cross-validated SE ? I fail to see how this is related to Data Science, this is rather related to pure probability/set math and how it fit data-mining itself. Note: Although this is an important concept for the tags referred this is not applied but rather pure math.
$endgroup$
– Pedro Henrique Monforte
9 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
a) The items that are frequent are $1,2,3,4,5,dots,20$ because these all appear in at least 5 baskets.
b)
(1) $5, 7 → 2$. Then $Confidence=frac12$
hence 5 and 7 will appear together in basket no. 35 and 70 and 2 will appear along with 7 and 5 in basket no. 70 so:
$$ Confidence = fracsupport(5,7cup2)support(5,7)= frac12 $$
(2) $2, 3, 4→ 5$. Then $Confidence=frac18 $
$2,3,4$ appear in baskets having basket number multiple of 12 ($LCM2,3,4$) i.e in basket no $12,24,...,60,.....,96$ and $2,3,4,5$ appear together only in basket no 60.
$→ Confidence=frac18$
edited 7 hours ago
Pedro Henrique Monforte
366111
answered 10 hours ago
user71202user71202
112
New contributor
user71202 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
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1 Answer
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1 Answer
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$begingroup$
a) The items that are frequent are $1,2,3,4,5,dots,20$ because these all appear in at least 5 baskets.
b)
(1) $5, 7 → 2$. Then $Confidence=frac12$
hence 5 and 7 will appear together in basket no. 35 and 70 and 2 will appear along with 7 and 5 in basket no. 70 so:
$$ Confidence = fracsupport(5,7cup2)support(5,7)= frac12 $$
(2) $2, 3, 4→ 5$. Then $Confidence=frac18 $
$2,3,4$ appear in baskets having basket number multiple of 12 ($LCM2,3,4$) i.e in basket no $12,24,...,60,.....,96$ and $2,3,4,5$ appear together only in basket no 60.
$→ Confidence=frac18$
edited 7 hours ago
Pedro Henrique Monforte
366111
answered 10 hours ago
user71202user71202
112
New contributor
user71202 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
a) The items that are frequent are $1,2,3,4,5,dots,20$ because these all appear in at least 5 baskets.
b)
(1) $5, 7 → 2$. Then $Confidence=frac12$
hence 5 and 7 will appear together in basket no. 35 and 70 and 2 will appear along with 7 and 5 in basket no. 70 so:
$$ Confidence = fracsupport(5,7cup2)support(5,7)= frac12 $$
(2) $2, 3, 4→ 5$. Then $Confidence=frac18 $
$2,3,4$ appear in baskets having basket number multiple of 12 ($LCM2,3,4$) i.e in basket no $12,24,...,60,.....,96$ and $2,3,4,5$ appear together only in basket no 60.
$→ Confidence=frac18$
edited 7 hours ago
Pedro Henrique Monforte
366111
answered 10 hours ago
user71202user71202
112
New contributor
user71202 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
a) The items that are frequent are $1,2,3,4,5,dots,20$ because these all appear in at least 5 baskets.
b)
(1) $5, 7 → 2$. Then $Confidence=frac12$
hence 5 and 7 will appear together in basket no. 35 and 70 and 2 will appear along with 7 and 5 in basket no. 70 so:
$$ Confidence = fracsupport(5,7cup2)support(5,7)= frac12 $$
(2) $2, 3, 4→ 5$. Then $Confidence=frac18 $
$2,3,4$ appear in baskets having basket number multiple of 12 ($LCM2,3,4$) i.e in basket no $12,24,...,60,.....,96$ and $2,3,4,5$ appear together only in basket no 60.
$→ Confidence=frac18$
edited 7 hours ago
Pedro Henrique Monforte
366111
answered 10 hours ago
user71202user71202
112
New contributor
user71202 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
a) The items that are frequent are $1,2,3,4,5,dots,20$ because these all appear in at least 5 baskets.
b)
(1) $5, 7 → 2$. Then $Confidence=frac12$
hence 5 and 7 will appear together in basket no. 35 and 70 and 2 will appear along with 7 and 5 in basket no. 70 so:
$$ Confidence = fracsupport(5,7cup2)support(5,7)= frac12 $$
(2) $2, 3, 4→ 5$. Then $Confidence=frac18 $
$2,3,4$ appear in baskets having basket number multiple of 12 ($LCM2,3,4$) i.e in basket no $12,24,...,60,.....,96$ and $2,3,4,5$ appear together only in basket no 60.
$→ Confidence=frac18$
edited 7 hours ago
Pedro Henrique Monforte
366111
answered 10 hours ago
user71202user71202
112
New contributor
user71202 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 7 hours ago
Pedro Henrique Monforte
366111
edited 7 hours ago
Pedro Henrique Monforte
366111
edited 7 hours ago
Pedro Henrique Monforte
366111
366111
answered 10 hours ago
user71202user71202
112
New contributor
user71202 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 10 hours ago
user71202user71202
112
answered 10 hours ago
user71202user71202
112
112
New contributor
user71202 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user71202 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user71202 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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$begingroup$
Isn't this best suited for Mathematics SE or maybe Cross-validated SE ? I fail to see how this is related to Data Science, this is rather related to pure probability/set math and how it fit data-mining itself. Note: Although this is an important concept for the tags referred this is not applied but rather pure math.
$endgroup$
– Pedro Henrique Monforte
9 hours ago