Why is arima in R one time step off? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)One step ahead forecast with new data collected sequentiallyauto.arima and predictionWhy are fitted values different from one-step ahead forecasts?Why can't my (auto.)arima-model forecast my time series?ARIMA: extract date/time information from ARIMA model(S)ARIMA — Hints with Time SeriesOne-Step Ahead ForecastARIMA(1,0,0) one-step ahead prediction in R/forecastARIMA forecasts are way offARIMA predicts the one step ahead of the actual prediction

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Why is arima in R one time step off?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)One step ahead forecast with new data collected sequentiallyauto.arima and predictionWhy are fitted values different from one-step ahead forecasts?Why can't my (auto.)arima-model forecast my time series?ARIMA: extract date/time information from ARIMA model(S)ARIMA — Hints with Time SeriesOne-Step Ahead ForecastARIMA(1,0,0) one-step ahead prediction in R/forecastARIMA forecasts are way offARIMA predicts the one step ahead of the actual prediction



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2












$begingroup$


I've recently noticed an odd behavior in a few timeseries methods. Let's fit an arima model (ar1) to the annual subspots data



library(forecast)
library(ggplot2)

mod_arima <- arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


Now, if we use forecast to get the fit on the model, it's a year off. Compare these two plots:



ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = fitted(mod_arima),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



To one where we delete the first value and tack on an NA at the end





ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = c(fitted(mod_arima)[-1], NA),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



The second lines up perfectly, while the first is obviously one year off. What's going on here?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
    $endgroup$
    – Richard Hardy
    4 hours ago

















2












$begingroup$


I've recently noticed an odd behavior in a few timeseries methods. Let's fit an arima model (ar1) to the annual subspots data



library(forecast)
library(ggplot2)

mod_arima <- arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


Now, if we use forecast to get the fit on the model, it's a year off. Compare these two plots:



ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = fitted(mod_arima),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



To one where we delete the first value and tack on an NA at the end





ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = c(fitted(mod_arima)[-1], NA),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



The second lines up perfectly, while the first is obviously one year off. What's going on here?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
    $endgroup$
    – Richard Hardy
    4 hours ago













2












2








2


1



$begingroup$


I've recently noticed an odd behavior in a few timeseries methods. Let's fit an arima model (ar1) to the annual subspots data



library(forecast)
library(ggplot2)

mod_arima <- arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


Now, if we use forecast to get the fit on the model, it's a year off. Compare these two plots:



ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = fitted(mod_arima),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



To one where we delete the first value and tack on an NA at the end





ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = c(fitted(mod_arima)[-1], NA),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



The second lines up perfectly, while the first is obviously one year off. What's going on here?










share|cite|improve this question









$endgroup$




I've recently noticed an odd behavior in a few timeseries methods. Let's fit an arima model (ar1) to the annual subspots data



library(forecast)
library(ggplot2)

mod_arima <- arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


Now, if we use forecast to get the fit on the model, it's a year off. Compare these two plots:



ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = fitted(mod_arima),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



To one where we delete the first value and tack on an NA at the end





ggplot(sun_dat,
aes(x = years, y = sunspots)) +
geom_line() +
geom_line(y = c(fitted(mod_arima)[-1], NA),
alpha = 0.5, lwd = 2, color = "blue")


enter image description here



The second lines up perfectly, while the first is obviously one year off. What's going on here?







r time-series forecasting arima






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 4 hours ago









jebyrnesjebyrnes

588415




588415







  • 1




    $begingroup$
    This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
    $endgroup$
    – Richard Hardy
    4 hours ago












  • 1




    $begingroup$
    This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
    $endgroup$
    – Richard Hardy
    4 hours ago







1




1




$begingroup$
This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
$endgroup$
– Richard Hardy
4 hours ago




$begingroup$
This is completely normal if the best prediction of $y_t+1$ is roughly $y_t$, which happens when the time series is a martingale difference sequence (typical e.g. for prices of shares and other financial instruments).
$endgroup$
– Richard Hardy
4 hours ago










2 Answers
2






active

oldest

votes


















2












$begingroup$

As Richard Hardy writes: if your prediction $haty_t+1$ of $y_t+1$ is pretty much your last observation $y_t$, then of course you would expect $haty_t+1$ to line up with $y_t$, which would show exactly as the one year lag you wonder about.



And if you specify



arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


then you fitted exactly that: an AR(1) model. The AR(1) coefficient is estimated to be about 0.81. (With an intercept. Also, if you add the year as a regressor, you will model a trend. Did you intend to do this?)



Incidentally, if you allow auto.arima() to fit a model, it will choose an ARIMA(2,1,3) model, which will not exhibit this lag:



sunspots



library(forecast)
model <- auto.arima(sunspot.year)
plot(sunspot.year)
lines(model$fit,col="red")


You could also include the known sunspot period of length 11, though auto.arima() won't automatically fit a SARIMA.






share|cite|improve this answer









$endgroup$




















    2












    $begingroup$

    You're fitting an $ARIMA(1,0,0)$ model to your data, which means that your fitted model has the form:



    $hatY_t+1-m = a(Y_t-m) + epsilon$



    So it looks like it's a year off, because all the model is doing is copying the value from the current year $Y_t$, with an adjustment $a$ and a drift term, and making that the prediction for the next year $hatY_t+1$.



    Your data looks highly cyclical, you might want to try fitting a seasonal ARIMA model instead of a simple AR(1) or AR(2).






    share|cite|improve this answer











    $endgroup$












    • $begingroup$
      @StephanKolassa updated. Thanks.
      $endgroup$
      – Skander H.
      4 hours ago










    • $begingroup$
      @StephanKolassa again, thanks.
      $endgroup$
      – Skander H.
      2 hours ago











    Your Answer








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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2












    $begingroup$

    As Richard Hardy writes: if your prediction $haty_t+1$ of $y_t+1$ is pretty much your last observation $y_t$, then of course you would expect $haty_t+1$ to line up with $y_t$, which would show exactly as the one year lag you wonder about.



    And if you specify



    arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


    then you fitted exactly that: an AR(1) model. The AR(1) coefficient is estimated to be about 0.81. (With an intercept. Also, if you add the year as a regressor, you will model a trend. Did you intend to do this?)



    Incidentally, if you allow auto.arima() to fit a model, it will choose an ARIMA(2,1,3) model, which will not exhibit this lag:



    sunspots



    library(forecast)
    model <- auto.arima(sunspot.year)
    plot(sunspot.year)
    lines(model$fit,col="red")


    You could also include the known sunspot period of length 11, though auto.arima() won't automatically fit a SARIMA.






    share|cite|improve this answer









    $endgroup$

















      2












      $begingroup$

      As Richard Hardy writes: if your prediction $haty_t+1$ of $y_t+1$ is pretty much your last observation $y_t$, then of course you would expect $haty_t+1$ to line up with $y_t$, which would show exactly as the one year lag you wonder about.



      And if you specify



      arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


      then you fitted exactly that: an AR(1) model. The AR(1) coefficient is estimated to be about 0.81. (With an intercept. Also, if you add the year as a regressor, you will model a trend. Did you intend to do this?)



      Incidentally, if you allow auto.arima() to fit a model, it will choose an ARIMA(2,1,3) model, which will not exhibit this lag:



      sunspots



      library(forecast)
      model <- auto.arima(sunspot.year)
      plot(sunspot.year)
      lines(model$fit,col="red")


      You could also include the known sunspot period of length 11, though auto.arima() won't automatically fit a SARIMA.






      share|cite|improve this answer









      $endgroup$















        2












        2








        2





        $begingroup$

        As Richard Hardy writes: if your prediction $haty_t+1$ of $y_t+1$ is pretty much your last observation $y_t$, then of course you would expect $haty_t+1$ to line up with $y_t$, which would show exactly as the one year lag you wonder about.



        And if you specify



        arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


        then you fitted exactly that: an AR(1) model. The AR(1) coefficient is estimated to be about 0.81. (With an intercept. Also, if you add the year as a regressor, you will model a trend. Did you intend to do this?)



        Incidentally, if you allow auto.arima() to fit a model, it will choose an ARIMA(2,1,3) model, which will not exhibit this lag:



        sunspots



        library(forecast)
        model <- auto.arima(sunspot.year)
        plot(sunspot.year)
        lines(model$fit,col="red")


        You could also include the known sunspot period of length 11, though auto.arima() won't automatically fit a SARIMA.






        share|cite|improve this answer









        $endgroup$



        As Richard Hardy writes: if your prediction $haty_t+1$ of $y_t+1$ is pretty much your last observation $y_t$, then of course you would expect $haty_t+1$ to line up with $y_t$, which would show exactly as the one year lag you wonder about.



        And if you specify



        arima(sunspot.year, c(1, 0, 0), xreg = 1700:1988)


        then you fitted exactly that: an AR(1) model. The AR(1) coefficient is estimated to be about 0.81. (With an intercept. Also, if you add the year as a regressor, you will model a trend. Did you intend to do this?)



        Incidentally, if you allow auto.arima() to fit a model, it will choose an ARIMA(2,1,3) model, which will not exhibit this lag:



        sunspots



        library(forecast)
        model <- auto.arima(sunspot.year)
        plot(sunspot.year)
        lines(model$fit,col="red")


        You could also include the known sunspot period of length 11, though auto.arima() won't automatically fit a SARIMA.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 4 hours ago









        Stephan KolassaStephan Kolassa

        48.2k8102181




        48.2k8102181























            2












            $begingroup$

            You're fitting an $ARIMA(1,0,0)$ model to your data, which means that your fitted model has the form:



            $hatY_t+1-m = a(Y_t-m) + epsilon$



            So it looks like it's a year off, because all the model is doing is copying the value from the current year $Y_t$, with an adjustment $a$ and a drift term, and making that the prediction for the next year $hatY_t+1$.



            Your data looks highly cyclical, you might want to try fitting a seasonal ARIMA model instead of a simple AR(1) or AR(2).






            share|cite|improve this answer











            $endgroup$












            • $begingroup$
              @StephanKolassa updated. Thanks.
              $endgroup$
              – Skander H.
              4 hours ago










            • $begingroup$
              @StephanKolassa again, thanks.
              $endgroup$
              – Skander H.
              2 hours ago















            2












            $begingroup$

            You're fitting an $ARIMA(1,0,0)$ model to your data, which means that your fitted model has the form:



            $hatY_t+1-m = a(Y_t-m) + epsilon$



            So it looks like it's a year off, because all the model is doing is copying the value from the current year $Y_t$, with an adjustment $a$ and a drift term, and making that the prediction for the next year $hatY_t+1$.



            Your data looks highly cyclical, you might want to try fitting a seasonal ARIMA model instead of a simple AR(1) or AR(2).






            share|cite|improve this answer











            $endgroup$












            • $begingroup$
              @StephanKolassa updated. Thanks.
              $endgroup$
              – Skander H.
              4 hours ago










            • $begingroup$
              @StephanKolassa again, thanks.
              $endgroup$
              – Skander H.
              2 hours ago













            2












            2








            2





            $begingroup$

            You're fitting an $ARIMA(1,0,0)$ model to your data, which means that your fitted model has the form:



            $hatY_t+1-m = a(Y_t-m) + epsilon$



            So it looks like it's a year off, because all the model is doing is copying the value from the current year $Y_t$, with an adjustment $a$ and a drift term, and making that the prediction for the next year $hatY_t+1$.



            Your data looks highly cyclical, you might want to try fitting a seasonal ARIMA model instead of a simple AR(1) or AR(2).






            share|cite|improve this answer











            $endgroup$



            You're fitting an $ARIMA(1,0,0)$ model to your data, which means that your fitted model has the form:



            $hatY_t+1-m = a(Y_t-m) + epsilon$



            So it looks like it's a year off, because all the model is doing is copying the value from the current year $Y_t$, with an adjustment $a$ and a drift term, and making that the prediction for the next year $hatY_t+1$.



            Your data looks highly cyclical, you might want to try fitting a seasonal ARIMA model instead of a simple AR(1) or AR(2).







            share|cite|improve this answer














            share|cite|improve this answer



            share|cite|improve this answer








            edited 2 hours ago









            Stephan Kolassa

            48.2k8102181




            48.2k8102181










            answered 4 hours ago









            Skander H.Skander H.

            3,9351232




            3,9351232











            • $begingroup$
              @StephanKolassa updated. Thanks.
              $endgroup$
              – Skander H.
              4 hours ago










            • $begingroup$
              @StephanKolassa again, thanks.
              $endgroup$
              – Skander H.
              2 hours ago
















            • $begingroup$
              @StephanKolassa updated. Thanks.
              $endgroup$
              – Skander H.
              4 hours ago










            • $begingroup$
              @StephanKolassa again, thanks.
              $endgroup$
              – Skander H.
              2 hours ago















            $begingroup$
            @StephanKolassa updated. Thanks.
            $endgroup$
            – Skander H.
            4 hours ago




            $begingroup$
            @StephanKolassa updated. Thanks.
            $endgroup$
            – Skander H.
            4 hours ago












            $begingroup$
            @StephanKolassa again, thanks.
            $endgroup$
            – Skander H.
            2 hours ago




            $begingroup$
            @StephanKolassa again, thanks.
            $endgroup$
            – Skander H.
            2 hours ago

















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