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Why boldmath fails in a tikz node?

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7

0

I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:

documentclass[border=10pt]standalone
usepackagetikz
begindocument
begintikzpicture
 path (0,0) node[draw]boldmath (+) (1,1);
endtikzpicture
enddocument

Fails to compile with a strange:

! Package tikz Error: Giving up on this path. Did you forget a semicolon?.

See the tikz package documentation for explanation.
Type H <return> for immediate help.
 ... 

l.6 path (0,0) node[draw]boldmath (+)
 (1,1);
? 

If I double the braces in the node, as

path (0,0) node[draw]boldmath (+) (1,1);

it works ok:

Is this expected behavior?

tikz-pgf boldmath

share|improve this question

asked 5 hours ago

RmanoRmano

8,34121649

• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  boldmath is not deprecated.
  
  – David Carlisle
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  I seem to recall that tikz only allows a certain number of expansions while looking for the ; and the full definition of boldmath is rather complicated so perhaps it is too much....
  
  – David Carlisle
  4 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
  
  – Rmano
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Not only unofficial it is completely wrong.
  
  – David Carlisle
  57 mins ago
  

  
  
  
  

add a comment | 

7

0

I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:

documentclass[border=10pt]standalone
usepackagetikz
begindocument
begintikzpicture
 path (0,0) node[draw]boldmath (+) (1,1);
endtikzpicture
enddocument

Fails to compile with a strange:

! Package tikz Error: Giving up on this path. Did you forget a semicolon?.

See the tikz package documentation for explanation.
Type H <return> for immediate help.
 ... 

l.6 path (0,0) node[draw]boldmath (+)
 (1,1);
? 

If I double the braces in the node, as

path (0,0) node[draw]boldmath (+) (1,1);

it works ok:

Is this expected behavior?

tikz-pgf boldmath

share|improve this question

asked 5 hours ago

RmanoRmano

8,34121649

• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  
  boldmath is not deprecated.
  
  – David Carlisle
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  I seem to recall that tikz only allows a certain number of expansions while looking for the ; and the full definition of boldmath is rather complicated so perhaps it is too much....
  
  – David Carlisle
  4 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
  
  – Rmano
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Not only unofficial it is completely wrong.
  
  – David Carlisle
  57 mins ago
  

  
  
  
  

add a comment | 

I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:

documentclass[border=10pt]standalone
usepackagetikz
begindocument
begintikzpicture
 path (0,0) node[draw]boldmath (+) (1,1);
endtikzpicture
enddocument

Fails to compile with a strange:

! Package tikz Error: Giving up on this path. Did you forget a semicolon?.

See the tikz package documentation for explanation.
Type H <return> for immediate help.
 ... 

l.6 path (0,0) node[draw]boldmath (+)
 (1,1);
? 

If I double the braces in the node, as

path (0,0) node[draw]boldmath (+) (1,1);

it works ok:

Is this expected behavior?

tikz-pgf boldmath

share|improve this question

asked 5 hours ago

RmanoRmano

8,34121649

documentclass[border=10pt]standalone
usepackagetikz
begindocument
begintikzpicture
 path (0,0) node[draw]boldmath (+) (1,1);
endtikzpicture
enddocument

! Package tikz Error: Giving up on this path. Did you forget a semicolon?.

See the tikz package documentation for explanation.
Type H <return> for immediate help.
 ... 

l.6 path (0,0) node[draw]boldmath (+)
 (1,1);
? 

path (0,0) node[draw]boldmath (+) (1,1);

share|improve this question

asked 5 hours ago

RmanoRmano

8,34121649

share|improve this question

asked 5 hours ago

RmanoRmano

8,34121649

asked 5 hours ago

RmanoRmano

8,34121649

asked 5 hours ago

RmanoRmano

8,34121649

1 Answer
1

active

oldest

votes

4

TikZ has the key font (as well as node font for such things) with which it works.

documentclass[border=10pt]standalone
usepackagetikz
begindocument
begintikzpicture
 path (1,0) node[draw,font=boldmath] (+);
 path (2,0) node[draw,node font=boldmath] (+);
 path (3,0) node[draw] (+);
endtikzpicture
enddocument

share|improve this answer

answered 3 hours ago

marmotmarmot

121k6159297

add a comment | 

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4

TikZ has the key font (as well as node font for such things) with which it works.

documentclass[border=10pt]standalone
usepackagetikz
begindocument
begintikzpicture
 path (1,0) node[draw,font=boldmath] (+);
 path (2,0) node[draw,node font=boldmath] (+);
 path (3,0) node[draw] (+);
endtikzpicture
enddocument

share|improve this answer

answered 3 hours ago

marmotmarmot

121k6159297

add a comment | 

4

TikZ has the key font (as well as node font for such things) with which it works.

documentclass[border=10pt]standalone
usepackagetikz
begindocument
begintikzpicture
 path (1,0) node[draw,font=boldmath] (+);
 path (2,0) node[draw,node font=boldmath] (+);
 path (3,0) node[draw] (+);
endtikzpicture
enddocument

share|improve this answer

answered 3 hours ago

marmotmarmot

121k6159297

add a comment | 

TikZ has the key font (as well as node font for such things) with which it works.

documentclass[border=10pt]standalone
usepackagetikz
begindocument
begintikzpicture
 path (1,0) node[draw,font=boldmath] (+);
 path (2,0) node[draw,node font=boldmath] (+);
 path (3,0) node[draw] (+);
endtikzpicture
enddocument

share|improve this answer

answered 3 hours ago

marmotmarmot

121k6159297

documentclass[border=10pt]standalone
usepackagetikz
begindocument
begintikzpicture
 path (1,0) node[draw,font=boldmath] (+);
 path (2,0) node[draw,node font=boldmath] (+);
 path (3,0) node[draw] (+);
endtikzpicture
enddocument

share|improve this answer

answered 3 hours ago

marmotmarmot

121k6159297

answered 3 hours ago

marmotmarmot

121k6159297

answered 3 hours ago

marmotmarmot

121k6159297