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Printing Feature Contributions in a Random Forest algorithm from the Treeinterpreter library leading to errors



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
2019 Moderator Election Q&A - Questionnaire
2019 Community Moderator Election ResultsSKNN regression problemPrimer on Random Forest AlgorithmUse a dataframe of word vectors as input feature for SVMBest way to represent data as features vectors in PythonMultivariable time-series forecast with NN vs RNNLSTM future steps prediction with shifted y_train relatively to X_trainHow to avoid covariate shift in python and distribute classes in each train and test phase?train_test_split function error. ValueError: Found input variables with inconsistent numbers of samples: [6, 27696]What's the difference between feature importance from Random Forest and Pearson correlation coefficientSequence classification using oneClass SVM










0












$begingroup$


I am working on a dataset where I predict the risks of developing pancreatic cancer with respect to a number of variables. I have created a random forest, and want to find the feature contributions. I have already used the "Treeinterpreter" library, resulting in a contributions array that is three-dimensional. I want to display the contributions in the array beside the name of the factor/variable. I have used the code below to do so, however, the code responsible for displaying the contributions does not work. I have tried multiple methods, including converting the dataframe to a numpy array, and other methods such as .all() and .any(). However, none are producing the desired result.



What can be the right way to display the feature contributions with respect to each of the feature it represents?



 # -*- coding: utf-8 -*-
"""
Created on Mon Apr 15 13:39:19 2019

@author: GoodManMcGee
"""

import pandas as pd
from sklearn.metrics import accuracy_score
from sklearn import tree
from sklearn.model_selection import train_test_split
from sklearn import preprocessing
from sklearn.metrics import confusion_matrix
from sklearn.ensemble import RandomForestClassifier
from IPython.display import Image
from sklearn.tree import export_graphviz
from treeinterpreter import treeinterpreter as ti
import matplotlib.pyplot as plt
import numpy as np
import itertools

data = pd.read_csv("pancreatic_cancer_smokers.csv")
target = data['case (1: case, 0: control)']
data.drop('case (1: case, 0: control)', axis=1, inplace=True)
x_train, x_test, y_train, y_test = train_test_split(data, target, test_size = 0.2)
clf = RandomForestClassifier(n_estimators=100)
clf.fit(x_train, y_train)
y_pred = clf.predict(x_test)
clf_accuracy = accuracy_score(y_test, y_pred)
clf_pred, clf_bias, contributions = ti.predict(clf, x_test)


#The code below was taken from DataDive's treeinterpreter tutorial.
#The aforementioned messages applies to all code between the underscores
#///////////////////////////////////////////

for i in range(len(x_test)):
print ("Instance", i)
print ("Bias (trainset mean)", clf_bias[i])
print ("Feature contributions:")
for c, feature in sorted(zip(contributions[i], data.feature_names),
key=lambda x: -abs(x[0])):
#An error occurs in the "data.feature_names" method in the code above:AttributeError: 'DataFrame' object has no attribute 'feature_names'. I have tried referenceing columns from datasets also, but that also leads to errors: ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
print (feature, round(c, 2))
print ("-"*20)
#///////////////////////////////////////////









share|improve this question







New contributor




Dhruv Upadhyay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
















    0












    $begingroup$


    I am working on a dataset where I predict the risks of developing pancreatic cancer with respect to a number of variables. I have created a random forest, and want to find the feature contributions. I have already used the "Treeinterpreter" library, resulting in a contributions array that is three-dimensional. I want to display the contributions in the array beside the name of the factor/variable. I have used the code below to do so, however, the code responsible for displaying the contributions does not work. I have tried multiple methods, including converting the dataframe to a numpy array, and other methods such as .all() and .any(). However, none are producing the desired result.



    What can be the right way to display the feature contributions with respect to each of the feature it represents?



     # -*- coding: utf-8 -*-
    """
    Created on Mon Apr 15 13:39:19 2019

    @author: GoodManMcGee
    """

    import pandas as pd
    from sklearn.metrics import accuracy_score
    from sklearn import tree
    from sklearn.model_selection import train_test_split
    from sklearn import preprocessing
    from sklearn.metrics import confusion_matrix
    from sklearn.ensemble import RandomForestClassifier
    from IPython.display import Image
    from sklearn.tree import export_graphviz
    from treeinterpreter import treeinterpreter as ti
    import matplotlib.pyplot as plt
    import numpy as np
    import itertools

    data = pd.read_csv("pancreatic_cancer_smokers.csv")
    target = data['case (1: case, 0: control)']
    data.drop('case (1: case, 0: control)', axis=1, inplace=True)
    x_train, x_test, y_train, y_test = train_test_split(data, target, test_size = 0.2)
    clf = RandomForestClassifier(n_estimators=100)
    clf.fit(x_train, y_train)
    y_pred = clf.predict(x_test)
    clf_accuracy = accuracy_score(y_test, y_pred)
    clf_pred, clf_bias, contributions = ti.predict(clf, x_test)


    #The code below was taken from DataDive's treeinterpreter tutorial.
    #The aforementioned messages applies to all code between the underscores
    #///////////////////////////////////////////

    for i in range(len(x_test)):
    print ("Instance", i)
    print ("Bias (trainset mean)", clf_bias[i])
    print ("Feature contributions:")
    for c, feature in sorted(zip(contributions[i], data.feature_names),
    key=lambda x: -abs(x[0])):
    #An error occurs in the "data.feature_names" method in the code above:AttributeError: 'DataFrame' object has no attribute 'feature_names'. I have tried referenceing columns from datasets also, but that also leads to errors: ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
    print (feature, round(c, 2))
    print ("-"*20)
    #///////////////////////////////////////////









    share|improve this question







    New contributor




    Dhruv Upadhyay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      0












      0








      0





      $begingroup$


      I am working on a dataset where I predict the risks of developing pancreatic cancer with respect to a number of variables. I have created a random forest, and want to find the feature contributions. I have already used the "Treeinterpreter" library, resulting in a contributions array that is three-dimensional. I want to display the contributions in the array beside the name of the factor/variable. I have used the code below to do so, however, the code responsible for displaying the contributions does not work. I have tried multiple methods, including converting the dataframe to a numpy array, and other methods such as .all() and .any(). However, none are producing the desired result.



      What can be the right way to display the feature contributions with respect to each of the feature it represents?



       # -*- coding: utf-8 -*-
      """
      Created on Mon Apr 15 13:39:19 2019

      @author: GoodManMcGee
      """

      import pandas as pd
      from sklearn.metrics import accuracy_score
      from sklearn import tree
      from sklearn.model_selection import train_test_split
      from sklearn import preprocessing
      from sklearn.metrics import confusion_matrix
      from sklearn.ensemble import RandomForestClassifier
      from IPython.display import Image
      from sklearn.tree import export_graphviz
      from treeinterpreter import treeinterpreter as ti
      import matplotlib.pyplot as plt
      import numpy as np
      import itertools

      data = pd.read_csv("pancreatic_cancer_smokers.csv")
      target = data['case (1: case, 0: control)']
      data.drop('case (1: case, 0: control)', axis=1, inplace=True)
      x_train, x_test, y_train, y_test = train_test_split(data, target, test_size = 0.2)
      clf = RandomForestClassifier(n_estimators=100)
      clf.fit(x_train, y_train)
      y_pred = clf.predict(x_test)
      clf_accuracy = accuracy_score(y_test, y_pred)
      clf_pred, clf_bias, contributions = ti.predict(clf, x_test)


      #The code below was taken from DataDive's treeinterpreter tutorial.
      #The aforementioned messages applies to all code between the underscores
      #///////////////////////////////////////////

      for i in range(len(x_test)):
      print ("Instance", i)
      print ("Bias (trainset mean)", clf_bias[i])
      print ("Feature contributions:")
      for c, feature in sorted(zip(contributions[i], data.feature_names),
      key=lambda x: -abs(x[0])):
      #An error occurs in the "data.feature_names" method in the code above:AttributeError: 'DataFrame' object has no attribute 'feature_names'. I have tried referenceing columns from datasets also, but that also leads to errors: ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
      print (feature, round(c, 2))
      print ("-"*20)
      #///////////////////////////////////////////









      share|improve this question







      New contributor




      Dhruv Upadhyay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I am working on a dataset where I predict the risks of developing pancreatic cancer with respect to a number of variables. I have created a random forest, and want to find the feature contributions. I have already used the "Treeinterpreter" library, resulting in a contributions array that is three-dimensional. I want to display the contributions in the array beside the name of the factor/variable. I have used the code below to do so, however, the code responsible for displaying the contributions does not work. I have tried multiple methods, including converting the dataframe to a numpy array, and other methods such as .all() and .any(). However, none are producing the desired result.



      What can be the right way to display the feature contributions with respect to each of the feature it represents?



       # -*- coding: utf-8 -*-
      """
      Created on Mon Apr 15 13:39:19 2019

      @author: GoodManMcGee
      """

      import pandas as pd
      from sklearn.metrics import accuracy_score
      from sklearn import tree
      from sklearn.model_selection import train_test_split
      from sklearn import preprocessing
      from sklearn.metrics import confusion_matrix
      from sklearn.ensemble import RandomForestClassifier
      from IPython.display import Image
      from sklearn.tree import export_graphviz
      from treeinterpreter import treeinterpreter as ti
      import matplotlib.pyplot as plt
      import numpy as np
      import itertools

      data = pd.read_csv("pancreatic_cancer_smokers.csv")
      target = data['case (1: case, 0: control)']
      data.drop('case (1: case, 0: control)', axis=1, inplace=True)
      x_train, x_test, y_train, y_test = train_test_split(data, target, test_size = 0.2)
      clf = RandomForestClassifier(n_estimators=100)
      clf.fit(x_train, y_train)
      y_pred = clf.predict(x_test)
      clf_accuracy = accuracy_score(y_test, y_pred)
      clf_pred, clf_bias, contributions = ti.predict(clf, x_test)


      #The code below was taken from DataDive's treeinterpreter tutorial.
      #The aforementioned messages applies to all code between the underscores
      #///////////////////////////////////////////

      for i in range(len(x_test)):
      print ("Instance", i)
      print ("Bias (trainset mean)", clf_bias[i])
      print ("Feature contributions:")
      for c, feature in sorted(zip(contributions[i], data.feature_names),
      key=lambda x: -abs(x[0])):
      #An error occurs in the "data.feature_names" method in the code above:AttributeError: 'DataFrame' object has no attribute 'feature_names'. I have tried referenceing columns from datasets also, but that also leads to errors: ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
      print (feature, round(c, 2))
      print ("-"*20)
      #///////////////////////////////////////////






      python random-forest feature-extraction






      share|improve this question







      New contributor




      Dhruv Upadhyay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Dhruv Upadhyay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      Dhruv Upadhyay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 2 hours ago









      Dhruv UpadhyayDhruv Upadhyay

      11




      11




      New contributor




      Dhruv Upadhyay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Dhruv Upadhyay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Dhruv Upadhyay is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















          1 Answer
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          $begingroup$

          Try this in the last part of your code:



          for i in range(len(X_test)):
          print ("Instance", i)
          print ("Bias (trainset mean)", clf3_bias[i])
          print ("Feature contributions:")
          for c, feature in sorted(zip(contributions[i,:,0], data.columns),key=lambda x: -abs(x[0])):
          print (feature, round(c, 2))
          print ("-"*20)


          The problem is that you are sorting contributions without taking into account that contributions is a 3D array and the column names is accesible with data.columns, not data.feature_names.






          share|improve this answer









          $endgroup$













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            $begingroup$

            Try this in the last part of your code:



            for i in range(len(X_test)):
            print ("Instance", i)
            print ("Bias (trainset mean)", clf3_bias[i])
            print ("Feature contributions:")
            for c, feature in sorted(zip(contributions[i,:,0], data.columns),key=lambda x: -abs(x[0])):
            print (feature, round(c, 2))
            print ("-"*20)


            The problem is that you are sorting contributions without taking into account that contributions is a 3D array and the column names is accesible with data.columns, not data.feature_names.






            share|improve this answer









            $endgroup$

















              0












              $begingroup$

              Try this in the last part of your code:



              for i in range(len(X_test)):
              print ("Instance", i)
              print ("Bias (trainset mean)", clf3_bias[i])
              print ("Feature contributions:")
              for c, feature in sorted(zip(contributions[i,:,0], data.columns),key=lambda x: -abs(x[0])):
              print (feature, round(c, 2))
              print ("-"*20)


              The problem is that you are sorting contributions without taking into account that contributions is a 3D array and the column names is accesible with data.columns, not data.feature_names.






              share|improve this answer









              $endgroup$















                0












                0








                0





                $begingroup$

                Try this in the last part of your code:



                for i in range(len(X_test)):
                print ("Instance", i)
                print ("Bias (trainset mean)", clf3_bias[i])
                print ("Feature contributions:")
                for c, feature in sorted(zip(contributions[i,:,0], data.columns),key=lambda x: -abs(x[0])):
                print (feature, round(c, 2))
                print ("-"*20)


                The problem is that you are sorting contributions without taking into account that contributions is a 3D array and the column names is accesible with data.columns, not data.feature_names.






                share|improve this answer









                $endgroup$



                Try this in the last part of your code:



                for i in range(len(X_test)):
                print ("Instance", i)
                print ("Bias (trainset mean)", clf3_bias[i])
                print ("Feature contributions:")
                for c, feature in sorted(zip(contributions[i,:,0], data.columns),key=lambda x: -abs(x[0])):
                print (feature, round(c, 2))
                print ("-"*20)


                The problem is that you are sorting contributions without taking into account that contributions is a 3D array and the column names is accesible with data.columns, not data.feature_names.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 1 hour ago









                Juan Esteban de la CalleJuan Esteban de la Calle

                55018




                55018




















                    Dhruv Upadhyay is a new contributor. Be nice, and check out our Code of Conduct.









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