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Do generators produce a fixed load?
Do generators run slower if the load is lower?Are there reversed rotation direction in generators (as back EMF in MOTORS)?How do generators in space transmit/ deposit energy back to Earth?
$begingroup$
As an example of my question, imagine I have a small generator attached to a bicycle pedals. If this generator is connected to one light bulb, how would it compare with the generator being connected to multiple bulbs?
My assumption is that, as you add more bulbs, either;
- The resistance on the pedals would remain the same, but you would now have to pedal faster in order to light the bulbs to the same brightness, or;
- It would become harder to pedal when the extra bulbs are added, but the same rpm would be needed to produce the same brightness.
Which (if either) of my assumptions is the correct one?
generator
asked 2 hours ago
PhysicsGuy123PhysicsGuy123
304
$endgroup$
add a comment |
$begingroup$
As an example of my question, imagine I have a small generator attached to a bicycle pedals. If this generator is connected to one light bulb, how would it compare with the generator being connected to multiple bulbs?
My assumption is that, as you add more bulbs, either;
- The resistance on the pedals would remain the same, but you would now have to pedal faster in order to light the bulbs to the same brightness, or;
- It would become harder to pedal when the extra bulbs are added, but the same rpm would be needed to produce the same brightness.
Which (if either) of my assumptions is the correct one?
generator
asked 2 hours ago
PhysicsGuy123PhysicsGuy123
304
$endgroup$
add a comment |
$begingroup$
As an example of my question, imagine I have a small generator attached to a bicycle pedals. If this generator is connected to one light bulb, how would it compare with the generator being connected to multiple bulbs?
My assumption is that, as you add more bulbs, either;
- The resistance on the pedals would remain the same, but you would now have to pedal faster in order to light the bulbs to the same brightness, or;
- It would become harder to pedal when the extra bulbs are added, but the same rpm would be needed to produce the same brightness.
Which (if either) of my assumptions is the correct one?
generator
asked 2 hours ago
PhysicsGuy123PhysicsGuy123
304
$endgroup$
As an example of my question, imagine I have a small generator attached to a bicycle pedals. If this generator is connected to one light bulb, how would it compare with the generator being connected to multiple bulbs?
My assumption is that, as you add more bulbs, either;
- The resistance on the pedals would remain the same, but you would now have to pedal faster in order to light the bulbs to the same brightness, or;
- It would become harder to pedal when the extra bulbs are added, but the same rpm would be needed to produce the same brightness.
Which (if either) of my assumptions is the correct one?
generator
generator
asked 2 hours ago
PhysicsGuy123PhysicsGuy123
304
asked 2 hours ago
PhysicsGuy123PhysicsGuy123
304
asked 2 hours ago
PhysicsGuy123PhysicsGuy123
304
asked 2 hours ago
PhysicsGuy123PhysicsGuy123
304
asked 2 hours ago
PhysicsGuy123PhysicsGuy123
304
304
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
As you add bulbs in parallel, the load impedance drops and to light all the bulbs you have to pedal harder. When the load impedance becomes less than the output impedance of the generator, then more work is expended in heating the generator coils than in lighting the bulbs. In the limit of near-zero load impedance (short circuit), all the pedal work is lost as I^2 x R losses in the generator windings. The pedal effort then does not change.
If you add bulbs in series, then to light all the bulbs you again have to pedal harder. However, in this case the load impedance grows bigger and less current is allowed to flow through the load. The pedal effort declines and the bulb string grows dimmer. In the limit of infinite load impedance, the current goes to zero and the pedal effort goes to zero too.
answered 1 hour ago
niels nielsenniels nielsen
3,6251211
$endgroup$
$begingroup$
Thanks for your answer. So, if instead of bulbs you had a motor how would this work? If you turned the motor off, I guess the mechanical resistance of the generator would be close to 0? And if you turned the motor up to its highest power, I guess it would require you to pedal much harder?
$endgroup$
– PhysicsGuy123
1 hour ago
$begingroup$
that's basically correct- but there are other details worth mentioning which I can't right at the moment- Niels
$endgroup$
– niels nielsen
52 mins ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
As you add bulbs in parallel, the load impedance drops and to light all the bulbs you have to pedal harder. When the load impedance becomes less than the output impedance of the generator, then more work is expended in heating the generator coils than in lighting the bulbs. In the limit of near-zero load impedance (short circuit), all the pedal work is lost as I^2 x R losses in the generator windings. The pedal effort then does not change.
If you add bulbs in series, then to light all the bulbs you again have to pedal harder. However, in this case the load impedance grows bigger and less current is allowed to flow through the load. The pedal effort declines and the bulb string grows dimmer. In the limit of infinite load impedance, the current goes to zero and the pedal effort goes to zero too.
answered 1 hour ago
niels nielsenniels nielsen
3,6251211
$endgroup$
$begingroup$
Thanks for your answer. So, if instead of bulbs you had a motor how would this work? If you turned the motor off, I guess the mechanical resistance of the generator would be close to 0? And if you turned the motor up to its highest power, I guess it would require you to pedal much harder?
$endgroup$
– PhysicsGuy123
1 hour ago
$begingroup$
that's basically correct- but there are other details worth mentioning which I can't right at the moment- Niels
$endgroup$
– niels nielsen
52 mins ago
add a comment |
$begingroup$
As you add bulbs in parallel, the load impedance drops and to light all the bulbs you have to pedal harder. When the load impedance becomes less than the output impedance of the generator, then more work is expended in heating the generator coils than in lighting the bulbs. In the limit of near-zero load impedance (short circuit), all the pedal work is lost as I^2 x R losses in the generator windings. The pedal effort then does not change.
If you add bulbs in series, then to light all the bulbs you again have to pedal harder. However, in this case the load impedance grows bigger and less current is allowed to flow through the load. The pedal effort declines and the bulb string grows dimmer. In the limit of infinite load impedance, the current goes to zero and the pedal effort goes to zero too.
answered 1 hour ago
niels nielsenniels nielsen
3,6251211
$endgroup$
$begingroup$
Thanks for your answer. So, if instead of bulbs you had a motor how would this work? If you turned the motor off, I guess the mechanical resistance of the generator would be close to 0? And if you turned the motor up to its highest power, I guess it would require you to pedal much harder?
$endgroup$
– PhysicsGuy123
1 hour ago
$begingroup$
that's basically correct- but there are other details worth mentioning which I can't right at the moment- Niels
$endgroup$
– niels nielsen
52 mins ago
add a comment |
$begingroup$
As you add bulbs in parallel, the load impedance drops and to light all the bulbs you have to pedal harder. When the load impedance becomes less than the output impedance of the generator, then more work is expended in heating the generator coils than in lighting the bulbs. In the limit of near-zero load impedance (short circuit), all the pedal work is lost as I^2 x R losses in the generator windings. The pedal effort then does not change.
If you add bulbs in series, then to light all the bulbs you again have to pedal harder. However, in this case the load impedance grows bigger and less current is allowed to flow through the load. The pedal effort declines and the bulb string grows dimmer. In the limit of infinite load impedance, the current goes to zero and the pedal effort goes to zero too.
answered 1 hour ago
niels nielsenniels nielsen
3,6251211
$endgroup$
As you add bulbs in parallel, the load impedance drops and to light all the bulbs you have to pedal harder. When the load impedance becomes less than the output impedance of the generator, then more work is expended in heating the generator coils than in lighting the bulbs. In the limit of near-zero load impedance (short circuit), all the pedal work is lost as I^2 x R losses in the generator windings. The pedal effort then does not change.
If you add bulbs in series, then to light all the bulbs you again have to pedal harder. However, in this case the load impedance grows bigger and less current is allowed to flow through the load. The pedal effort declines and the bulb string grows dimmer. In the limit of infinite load impedance, the current goes to zero and the pedal effort goes to zero too.
answered 1 hour ago
niels nielsenniels nielsen
3,6251211
answered 1 hour ago
niels nielsenniels nielsen
3,6251211
answered 1 hour ago
niels nielsenniels nielsen
3,6251211
answered 1 hour ago
niels nielsenniels nielsen
3,6251211
3,6251211
$begingroup$
Thanks for your answer. So, if instead of bulbs you had a motor how would this work? If you turned the motor off, I guess the mechanical resistance of the generator would be close to 0? And if you turned the motor up to its highest power, I guess it would require you to pedal much harder?
$endgroup$
– PhysicsGuy123
1 hour ago
$begingroup$
that's basically correct- but there are other details worth mentioning which I can't right at the moment- Niels
$endgroup$
– niels nielsen
52 mins ago
add a comment |
$begingroup$
Thanks for your answer. So, if instead of bulbs you had a motor how would this work? If you turned the motor off, I guess the mechanical resistance of the generator would be close to 0? And if you turned the motor up to its highest power, I guess it would require you to pedal much harder?
$endgroup$
– PhysicsGuy123
1 hour ago
$begingroup$
that's basically correct- but there are other details worth mentioning which I can't right at the moment- Niels
$endgroup$
– niels nielsen
52 mins ago
$begingroup$
Thanks for your answer. So, if instead of bulbs you had a motor how would this work? If you turned the motor off, I guess the mechanical resistance of the generator would be close to 0? And if you turned the motor up to its highest power, I guess it would require you to pedal much harder?
$endgroup$
– PhysicsGuy123
1 hour ago
$begingroup$
Thanks for your answer. So, if instead of bulbs you had a motor how would this work? If you turned the motor off, I guess the mechanical resistance of the generator would be close to 0? And if you turned the motor up to its highest power, I guess it would require you to pedal much harder?
$endgroup$
– PhysicsGuy123
1 hour ago
$begingroup$
that's basically correct- but there are other details worth mentioning which I can't right at the moment- Niels
$endgroup$
– niels nielsen
52 mins ago
$begingroup$
that's basically correct- but there are other details worth mentioning which I can't right at the moment- Niels
$endgroup$
– niels nielsen
52 mins ago
add a comment |
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