Cauchy Sequence Characterized only By Directly Neighbouring Sequence Members Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Series constructed from a cauchy sequenceRelations among notions of convergenceCauchy Sequence proof with boundsProof review - (lack of rigour?) Convergent sequence iff Cauchy without Bolzano-WeierstrassProof verification regarding whether a certain property of a sequence implies that it is Cauchy.Why is the sequence $x(n) = log n$ **not** Cauchy?Mathematical Analysis Cauchy SequenceThat a sequence is Cauchy implies it's bounded.Determine if this specific sequence is a Cauchy sequenceCauchy sequence and boundedness
Antler Helmet: Can it work?
Why don't the Weasley twins use magic outside of school if the Trace can only find the location of spells cast?
Stop battery usage [Ubuntu 18]
Is above average number of years spent on PhD considered a red flag in future academia or industry positions?
When is phishing education going too far?
Why is there no army of Iron-Mans in the MCU?
What did Darwin mean by 'squib' here?
How to stop my camera from exagerrating differences in skin colour?
Complexity of many constant time steps with occasional logarithmic steps
Determine whether f is a function, an injection, a surjection
What do you call the holes in a flute?
Active filter with series inductor and resistor - do these exist?
Is there a documented rationale why the House Ways and Means chairman can demand tax info?
Is there folklore associating late breastfeeding with low intelligence and/or gullibility?
Strange behaviour of Check
Did the new image of black hole confirm the general theory of relativity?
How can I make names more distinctive without making them longer?
3 doors, three guards, one stone
Using "nakedly" instead of "with nothing on"
How is simplicity better than precision and clarity in prose?
What items from the Roman-age tech-level could be used to deter all creatures from entering a small area?
What's the point in a preamp?
Working around an AWS network ACL rule limit
How to say that you spent the night with someone, you were only sleeping and nothing else?
Cauchy Sequence Characterized only By Directly Neighbouring Sequence Members
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Series constructed from a cauchy sequenceRelations among notions of convergenceCauchy Sequence proof with boundsProof review - (lack of rigour?) Convergent sequence iff Cauchy without Bolzano-WeierstrassProof verification regarding whether a certain property of a sequence implies that it is Cauchy.Why is the sequence $x(n) = log n$ **not** Cauchy?Mathematical Analysis Cauchy SequenceThat a sequence is Cauchy implies it's bounded.Determine if this specific sequence is a Cauchy sequenceCauchy sequence and boundedness
$begingroup$
Let $(a_n)$ be a sequence of real numbers, for which it holds, that
$$ lim_n rightarrow infty lvert a_n+1-a_n rvert = 0. $$ Does this already imply, that $(a_n)$ is a Cauchy sequence?
limits cauchy-sequences
$endgroup$
add a comment |
$begingroup$
Let $(a_n)$ be a sequence of real numbers, for which it holds, that
$$ lim_n rightarrow infty lvert a_n+1-a_n rvert = 0. $$ Does this already imply, that $(a_n)$ is a Cauchy sequence?
limits cauchy-sequences
$endgroup$
add a comment |
$begingroup$
Let $(a_n)$ be a sequence of real numbers, for which it holds, that
$$ lim_n rightarrow infty lvert a_n+1-a_n rvert = 0. $$ Does this already imply, that $(a_n)$ is a Cauchy sequence?
limits cauchy-sequences
$endgroup$
Let $(a_n)$ be a sequence of real numbers, for which it holds, that
$$ lim_n rightarrow infty lvert a_n+1-a_n rvert = 0. $$ Does this already imply, that $(a_n)$ is a Cauchy sequence?
limits cauchy-sequences
limits cauchy-sequences
asked 4 hours ago
Joker123Joker123
632313
632313
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Unfortunately not. Consider
$$a_n:=sum_i=1^nfrac1i.$$
We find $a_n+1-a_n=1/(n+1)to 0,$ but $lim_ntoinftya_n=infty,$ hence $a_n_ninmathbbN$ is not a cauchy sequence.
$endgroup$
add a comment |
$begingroup$
No. The sequence $a_n=sum_k=1^nfrac1k$ is a counterexample.
$endgroup$
add a comment |
$begingroup$
Counterexample: $a_n = sqrtn$. Clearly this sequence does not converge. But
$$
a_n+1 - a_n = sqrtn+1 - sqrtn = frac(sqrtn+1 - sqrtn)(sqrtn+1 + sqrtn)(sqrtn+1 + sqrtn) = frac1sqrtn+1 + sqrtn to 0 , .
$$
$endgroup$
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3188087%2fcauchy-sequence-characterized-only-by-directly-neighbouring-sequence-members%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Unfortunately not. Consider
$$a_n:=sum_i=1^nfrac1i.$$
We find $a_n+1-a_n=1/(n+1)to 0,$ but $lim_ntoinftya_n=infty,$ hence $a_n_ninmathbbN$ is not a cauchy sequence.
$endgroup$
add a comment |
$begingroup$
Unfortunately not. Consider
$$a_n:=sum_i=1^nfrac1i.$$
We find $a_n+1-a_n=1/(n+1)to 0,$ but $lim_ntoinftya_n=infty,$ hence $a_n_ninmathbbN$ is not a cauchy sequence.
$endgroup$
add a comment |
$begingroup$
Unfortunately not. Consider
$$a_n:=sum_i=1^nfrac1i.$$
We find $a_n+1-a_n=1/(n+1)to 0,$ but $lim_ntoinftya_n=infty,$ hence $a_n_ninmathbbN$ is not a cauchy sequence.
$endgroup$
Unfortunately not. Consider
$$a_n:=sum_i=1^nfrac1i.$$
We find $a_n+1-a_n=1/(n+1)to 0,$ but $lim_ntoinftya_n=infty,$ hence $a_n_ninmathbbN$ is not a cauchy sequence.
edited 4 hours ago
HAMIDINE SOUMARE
2,181214
2,181214
answered 4 hours ago
MelodyMelody
1,27012
1,27012
add a comment |
add a comment |
$begingroup$
No. The sequence $a_n=sum_k=1^nfrac1k$ is a counterexample.
$endgroup$
add a comment |
$begingroup$
No. The sequence $a_n=sum_k=1^nfrac1k$ is a counterexample.
$endgroup$
add a comment |
$begingroup$
No. The sequence $a_n=sum_k=1^nfrac1k$ is a counterexample.
$endgroup$
No. The sequence $a_n=sum_k=1^nfrac1k$ is a counterexample.
answered 4 hours ago
MarkMark
10.6k1622
10.6k1622
add a comment |
add a comment |
$begingroup$
Counterexample: $a_n = sqrtn$. Clearly this sequence does not converge. But
$$
a_n+1 - a_n = sqrtn+1 - sqrtn = frac(sqrtn+1 - sqrtn)(sqrtn+1 + sqrtn)(sqrtn+1 + sqrtn) = frac1sqrtn+1 + sqrtn to 0 , .
$$
$endgroup$
add a comment |
$begingroup$
Counterexample: $a_n = sqrtn$. Clearly this sequence does not converge. But
$$
a_n+1 - a_n = sqrtn+1 - sqrtn = frac(sqrtn+1 - sqrtn)(sqrtn+1 + sqrtn)(sqrtn+1 + sqrtn) = frac1sqrtn+1 + sqrtn to 0 , .
$$
$endgroup$
add a comment |
$begingroup$
Counterexample: $a_n = sqrtn$. Clearly this sequence does not converge. But
$$
a_n+1 - a_n = sqrtn+1 - sqrtn = frac(sqrtn+1 - sqrtn)(sqrtn+1 + sqrtn)(sqrtn+1 + sqrtn) = frac1sqrtn+1 + sqrtn to 0 , .
$$
$endgroup$
Counterexample: $a_n = sqrtn$. Clearly this sequence does not converge. But
$$
a_n+1 - a_n = sqrtn+1 - sqrtn = frac(sqrtn+1 - sqrtn)(sqrtn+1 + sqrtn)(sqrtn+1 + sqrtn) = frac1sqrtn+1 + sqrtn to 0 , .
$$
answered 3 hours ago
Hans EnglerHans Engler
10.7k11836
10.7k11836
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3188087%2fcauchy-sequence-characterized-only-by-directly-neighbouring-sequence-members%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown