Compilation of a 2d array and a 1d array The Next CEO of Stack OverflowWhat is the most efficient way to add rows and columns to a matrix?Minor question about optimally increasing last item of a listGetting directly a packed array of repeated packed arraysHow to join and 'multiply' two lists?Finding distance through pair of pointsEfficiently create an array of values of a function2D array summation operationsHow to add zeros before and after each element in a list?Select an element from each matrix row/column specified by a vectorBasis enumeration of large lists
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Compilation of a 2d array and a 1d array
The Next CEO of Stack OverflowWhat is the most efficient way to add rows and columns to a matrix?Minor question about optimally increasing last item of a listGetting directly a packed array of repeated packed arraysHow to join and 'multiply' two lists?Finding distance through pair of pointsEfficiently create an array of values of a function2D array summation operationsHow to add zeros before and after each element in a list?Select an element from each matrix row/column specified by a vectorBasis enumeration of large lists
$begingroup$
With a list say x1,y1,x2,y2… and a list z1, what is the best way to create a list x1,y1,z1,x2,y2,z1,x3,y3,z1…
list-manipulation
$endgroup$
add a comment |
$begingroup$
With a list say x1,y1,x2,y2… and a list z1, what is the best way to create a list x1,y1,z1,x2,y2,z1,x3,y3,z1…
list-manipulation
$endgroup$
add a comment |
$begingroup$
With a list say x1,y1,x2,y2… and a list z1, what is the best way to create a list x1,y1,z1,x2,y2,z1,x3,y3,z1…
list-manipulation
$endgroup$
With a list say x1,y1,x2,y2… and a list z1, what is the best way to create a list x1,y1,z1,x2,y2,z1,x3,y3,z1…
list-manipulation
list-manipulation
edited 22 mins ago
J. M. is slightly pensive♦
98.9k10311467
98.9k10311467
asked 5 hours ago
tombom21tombom21
133
133
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You can use PadRight
:
PadRight[
x1, y1, x2, y2,
Automatic, 3,
z1
]
x1, y1, z1, x2, y2, z1
Or ArrayPad
:
ArrayPad[
x1, y1, x2, y2, x3, y3,
0,0,0,1,
z1
]
x1, y1, z1, x2, y2, z1, x3, y3, z1
$endgroup$
add a comment |
$begingroup$
n = 1000000;
a = RandomReal[-1, 1, n, 2];
b = ConstantArray[0., 1];
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First
0.016
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can use PadRight
:
PadRight[
x1, y1, x2, y2,
Automatic, 3,
z1
]
x1, y1, z1, x2, y2, z1
Or ArrayPad
:
ArrayPad[
x1, y1, x2, y2, x3, y3,
0,0,0,1,
z1
]
x1, y1, z1, x2, y2, z1, x3, y3, z1
$endgroup$
add a comment |
$begingroup$
You can use PadRight
:
PadRight[
x1, y1, x2, y2,
Automatic, 3,
z1
]
x1, y1, z1, x2, y2, z1
Or ArrayPad
:
ArrayPad[
x1, y1, x2, y2, x3, y3,
0,0,0,1,
z1
]
x1, y1, z1, x2, y2, z1, x3, y3, z1
$endgroup$
add a comment |
$begingroup$
You can use PadRight
:
PadRight[
x1, y1, x2, y2,
Automatic, 3,
z1
]
x1, y1, z1, x2, y2, z1
Or ArrayPad
:
ArrayPad[
x1, y1, x2, y2, x3, y3,
0,0,0,1,
z1
]
x1, y1, z1, x2, y2, z1, x3, y3, z1
$endgroup$
You can use PadRight
:
PadRight[
x1, y1, x2, y2,
Automatic, 3,
z1
]
x1, y1, z1, x2, y2, z1
Or ArrayPad
:
ArrayPad[
x1, y1, x2, y2, x3, y3,
0,0,0,1,
z1
]
x1, y1, z1, x2, y2, z1, x3, y3, z1
answered 5 hours ago
Carl WollCarl Woll
72.2k395186
72.2k395186
add a comment |
add a comment |
$begingroup$
n = 1000000;
a = RandomReal[-1, 1, n, 2];
b = ConstantArray[0., 1];
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First
0.016
$endgroup$
add a comment |
$begingroup$
n = 1000000;
a = RandomReal[-1, 1, n, 2];
b = ConstantArray[0., 1];
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First
0.016
$endgroup$
add a comment |
$begingroup$
n = 1000000;
a = RandomReal[-1, 1, n, 2];
b = ConstantArray[0., 1];
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First
0.016
$endgroup$
n = 1000000;
a = RandomReal[-1, 1, n, 2];
b = ConstantArray[0., 1];
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First
0.016
answered 5 hours ago
Henrik SchumacherHenrik Schumacher
58.7k581162
58.7k581162
add a comment |
add a comment |
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