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Redefining symbol midway through a document
The Next CEO of Stack OverflowConflict between color, graphicx and libertineWish to design new integral symbol with infinity symbol through itTeXLive/PDFTeX fonts loading problemConverting all numbers in document to set number of decimal placesGenerating PDF/A-1b compliant documents using pdfx and pdfLaTeXUndefined control sequence Hy@MakeCurrentHrefAuto when using tex4htRedefining math symbols like eta (with ensuremath)Redefining command outside math modebar through letter in mathmodeAdd an iterative layer to IfFileExists to check each graphicspath
I am trying to have one command (phi
) draw two different symbols (varphi
and regular phi
) in the same document.
I have tried this with the below:
documentclassarticle
usepackageamsmath, amssymb
newcommandoldphiphi
renewcommandphivarphi
begindocument
$phi$
renewcommandphioldphi
$phi$
enddocument
But this wont compile (with pdftex or TexMaker), it seem like it gets stuck in a loop and wont create a pdf, but I can't see why?
Or is there a better way to achieve this?
math-mode macros pdftex symbols
add a comment |
I am trying to have one command (phi
) draw two different symbols (varphi
and regular phi
) in the same document.
I have tried this with the below:
documentclassarticle
usepackageamsmath, amssymb
newcommandoldphiphi
renewcommandphivarphi
begindocument
$phi$
renewcommandphioldphi
$phi$
enddocument
But this wont compile (with pdftex or TexMaker), it seem like it gets stuck in a loop and wont create a pdf, but I can't see why?
Or is there a better way to achieve this?
math-mode macros pdftex symbols
Yes: using phi` when you want it, and `varphi`` when it is the one you need.
– Bernard
4 hours ago
@Bernard I know that's the simplest way to do it really, but it would mean writing way to many extra letters :P
– Sergestus
4 hours ago
add a comment |
I am trying to have one command (phi
) draw two different symbols (varphi
and regular phi
) in the same document.
I have tried this with the below:
documentclassarticle
usepackageamsmath, amssymb
newcommandoldphiphi
renewcommandphivarphi
begindocument
$phi$
renewcommandphioldphi
$phi$
enddocument
But this wont compile (with pdftex or TexMaker), it seem like it gets stuck in a loop and wont create a pdf, but I can't see why?
Or is there a better way to achieve this?
math-mode macros pdftex symbols
I am trying to have one command (phi
) draw two different symbols (varphi
and regular phi
) in the same document.
I have tried this with the below:
documentclassarticle
usepackageamsmath, amssymb
newcommandoldphiphi
renewcommandphivarphi
begindocument
$phi$
renewcommandphioldphi
$phi$
enddocument
But this wont compile (with pdftex or TexMaker), it seem like it gets stuck in a loop and wont create a pdf, but I can't see why?
Or is there a better way to achieve this?
math-mode macros pdftex symbols
math-mode macros pdftex symbols
edited 4 hours ago
Sergestus
asked 5 hours ago
SergestusSergestus
254
254
Yes: using phi` when you want it, and `varphi`` when it is the one you need.
– Bernard
4 hours ago
@Bernard I know that's the simplest way to do it really, but it would mean writing way to many extra letters :P
– Sergestus
4 hours ago
add a comment |
Yes: using phi` when you want it, and `varphi`` when it is the one you need.
– Bernard
4 hours ago
@Bernard I know that's the simplest way to do it really, but it would mean writing way to many extra letters :P
– Sergestus
4 hours ago
Yes: using phi` when you want it, and `varphi`` when it is the one you need.
– Bernard
4 hours ago
Yes: using phi` when you want it, and `varphi`` when it is the one you need.
– Bernard
4 hours ago
@Bernard I know that's the simplest way to do it really, but it would mean writing way to many extra letters :P
– Sergestus
4 hours ago
@Bernard I know that's the simplest way to do it really, but it would mean writing way to many extra letters :P
– Sergestus
4 hours ago
add a comment |
2 Answers
2
active
oldest
votes
With let
, it works:
documentclassarticle
usepackageamsmath, amssymb
letoldphi=phi
letphi=varphi
begindocument
$phi$
letphi=oldphi
$phi$
letphi=varphi
$phi$
letphi=oldphi
$phi$
enddocument
Great! I had just reached the same conclusion below, thanks!
– Sergestus
4 hours ago
1
Oh! I see. Great minds think together! :o)
– Bernard
4 hours ago
add a comment |
I have solved this myself using let
and so post this for posterity.
documentclassarticle
usepackageamsmath, amssymb
letoldphiphi
letphivarphi
begindocument
$phi$
letphioldphi
$phi$
enddocument
My understanding is that newcommandxy
simply replaces "a
" with "b
" so can become circular, whereas letab
actually sets a
to the value of b
, so resolves any self-referencing issues.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
With let
, it works:
documentclassarticle
usepackageamsmath, amssymb
letoldphi=phi
letphi=varphi
begindocument
$phi$
letphi=oldphi
$phi$
letphi=varphi
$phi$
letphi=oldphi
$phi$
enddocument
Great! I had just reached the same conclusion below, thanks!
– Sergestus
4 hours ago
1
Oh! I see. Great minds think together! :o)
– Bernard
4 hours ago
add a comment |
With let
, it works:
documentclassarticle
usepackageamsmath, amssymb
letoldphi=phi
letphi=varphi
begindocument
$phi$
letphi=oldphi
$phi$
letphi=varphi
$phi$
letphi=oldphi
$phi$
enddocument
Great! I had just reached the same conclusion below, thanks!
– Sergestus
4 hours ago
1
Oh! I see. Great minds think together! :o)
– Bernard
4 hours ago
add a comment |
With let
, it works:
documentclassarticle
usepackageamsmath, amssymb
letoldphi=phi
letphi=varphi
begindocument
$phi$
letphi=oldphi
$phi$
letphi=varphi
$phi$
letphi=oldphi
$phi$
enddocument
With let
, it works:
documentclassarticle
usepackageamsmath, amssymb
letoldphi=phi
letphi=varphi
begindocument
$phi$
letphi=oldphi
$phi$
letphi=varphi
$phi$
letphi=oldphi
$phi$
enddocument
answered 4 hours ago
BernardBernard
175k776207
175k776207
Great! I had just reached the same conclusion below, thanks!
– Sergestus
4 hours ago
1
Oh! I see. Great minds think together! :o)
– Bernard
4 hours ago
add a comment |
Great! I had just reached the same conclusion below, thanks!
– Sergestus
4 hours ago
1
Oh! I see. Great minds think together! :o)
– Bernard
4 hours ago
Great! I had just reached the same conclusion below, thanks!
– Sergestus
4 hours ago
Great! I had just reached the same conclusion below, thanks!
– Sergestus
4 hours ago
1
1
Oh! I see. Great minds think together! :o)
– Bernard
4 hours ago
Oh! I see. Great minds think together! :o)
– Bernard
4 hours ago
add a comment |
I have solved this myself using let
and so post this for posterity.
documentclassarticle
usepackageamsmath, amssymb
letoldphiphi
letphivarphi
begindocument
$phi$
letphioldphi
$phi$
enddocument
My understanding is that newcommandxy
simply replaces "a
" with "b
" so can become circular, whereas letab
actually sets a
to the value of b
, so resolves any self-referencing issues.
add a comment |
I have solved this myself using let
and so post this for posterity.
documentclassarticle
usepackageamsmath, amssymb
letoldphiphi
letphivarphi
begindocument
$phi$
letphioldphi
$phi$
enddocument
My understanding is that newcommandxy
simply replaces "a
" with "b
" so can become circular, whereas letab
actually sets a
to the value of b
, so resolves any self-referencing issues.
add a comment |
I have solved this myself using let
and so post this for posterity.
documentclassarticle
usepackageamsmath, amssymb
letoldphiphi
letphivarphi
begindocument
$phi$
letphioldphi
$phi$
enddocument
My understanding is that newcommandxy
simply replaces "a
" with "b
" so can become circular, whereas letab
actually sets a
to the value of b
, so resolves any self-referencing issues.
I have solved this myself using let
and so post this for posterity.
documentclassarticle
usepackageamsmath, amssymb
letoldphiphi
letphivarphi
begindocument
$phi$
letphioldphi
$phi$
enddocument
My understanding is that newcommandxy
simply replaces "a
" with "b
" so can become circular, whereas letab
actually sets a
to the value of b
, so resolves any self-referencing issues.
answered 4 hours ago
SergestusSergestus
254
254
add a comment |
add a comment |
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Yes: using phi` when you want it, and `varphi`` when it is the one you need.
– Bernard
4 hours ago
@Bernard I know that's the simplest way to do it really, but it would mean writing way to many extra letters :P
– Sergestus
4 hours ago