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Google Sheets: how to find max value in column B, corresponding values in column A, and max among these


How to use the CASE function in Trifacta / Google DataPrep Transform Builder to change the values of a column based on two 'bins' of strings?How to integrate google cloud with dropbox and jupyter notebook using tensorflow













0












$begingroup$


I have two numeric columns, A and B. I want to find the max value in column B, which will return multiple rows. Then I want to find the max value in column A from among these rows.



A B
5 315
7 315
10 275


The function should return:



 7 315


It would be fine if this were a combination of two functions - one that finds the max value in B (315), and another that finds the corresponding max value in A (7). That's how I'm trying it right now using:



=index(A2:B10,match(max(B2:B10),B2:B10,0))


But this solution only finds the latest row that has column B's max value:



 5 315


Someone suggested I use the query function, but I couldn't get that to work either.










share|improve this question







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    0












    $begingroup$


    I have two numeric columns, A and B. I want to find the max value in column B, which will return multiple rows. Then I want to find the max value in column A from among these rows.



    A B
    5 315
    7 315
    10 275


    The function should return:



     7 315


    It would be fine if this were a combination of two functions - one that finds the max value in B (315), and another that finds the corresponding max value in A (7). That's how I'm trying it right now using:



    =index(A2:B10,match(max(B2:B10),B2:B10,0))


    But this solution only finds the latest row that has column B's max value:



     5 315


    Someone suggested I use the query function, but I couldn't get that to work either.










    share|improve this question







    New contributor




    adriandahlin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      0












      0








      0





      $begingroup$


      I have two numeric columns, A and B. I want to find the max value in column B, which will return multiple rows. Then I want to find the max value in column A from among these rows.



      A B
      5 315
      7 315
      10 275


      The function should return:



       7 315


      It would be fine if this were a combination of two functions - one that finds the max value in B (315), and another that finds the corresponding max value in A (7). That's how I'm trying it right now using:



      =index(A2:B10,match(max(B2:B10),B2:B10,0))


      But this solution only finds the latest row that has column B's max value:



       5 315


      Someone suggested I use the query function, but I couldn't get that to work either.










      share|improve this question







      New contributor




      adriandahlin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I have two numeric columns, A and B. I want to find the max value in column B, which will return multiple rows. Then I want to find the max value in column A from among these rows.



      A B
      5 315
      7 315
      10 275


      The function should return:



       7 315


      It would be fine if this were a combination of two functions - one that finds the max value in B (315), and another that finds the corresponding max value in A (7). That's how I'm trying it right now using:



      =index(A2:B10,match(max(B2:B10),B2:B10,0))


      But this solution only finds the latest row that has column B's max value:



       5 315


      Someone suggested I use the query function, but I couldn't get that to work either.







      google






      share|improve this question







      New contributor




      adriandahlin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




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      share|improve this question




      share|improve this question






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      asked Mar 15 at 17:16









      adriandahlinadriandahlin

      32




      32




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          2 Answers
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          0












          $begingroup$

          Suppose you have data in the columns A, B from row 2 to 4. Put MAX(B2:B4) somewhere (in this example, I put it in B6). Then for the corresponding max in A you can use the formula MAX(ARRAYFORMULA(IF(B2:B4 = $B$6,A2:A4))).






          share|improve this answer








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          $endgroup$












          • $begingroup$
            That works! Also, see the method I figured out in my separate answer.
            $endgroup$
            – adriandahlin
            2 hours ago


















          0












          $begingroup$

          I figured this out using the query function and referencing a specific cell.



          First, as @dcolazin suggests, you put the max of column B in a cell (I chose B1):



          =max(B2:B10)


          Then you do this in cell A1 (notice the "&&" to reference a cell within your SQL query):



          =query(A2:B10,"select max(A) where B >= "&B1&"")





          share|improve this answer








          New contributor




          adriandahlin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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            2 Answers
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            2 Answers
            2






            active

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            active

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            active

            oldest

            votes









            0












            $begingroup$

            Suppose you have data in the columns A, B from row 2 to 4. Put MAX(B2:B4) somewhere (in this example, I put it in B6). Then for the corresponding max in A you can use the formula MAX(ARRAYFORMULA(IF(B2:B4 = $B$6,A2:A4))).






            share|improve this answer








            New contributor




            dcolazin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$












            • $begingroup$
              That works! Also, see the method I figured out in my separate answer.
              $endgroup$
              – adriandahlin
              2 hours ago















            0












            $begingroup$

            Suppose you have data in the columns A, B from row 2 to 4. Put MAX(B2:B4) somewhere (in this example, I put it in B6). Then for the corresponding max in A you can use the formula MAX(ARRAYFORMULA(IF(B2:B4 = $B$6,A2:A4))).






            share|improve this answer








            New contributor




            dcolazin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$












            • $begingroup$
              That works! Also, see the method I figured out in my separate answer.
              $endgroup$
              – adriandahlin
              2 hours ago













            0












            0








            0





            $begingroup$

            Suppose you have data in the columns A, B from row 2 to 4. Put MAX(B2:B4) somewhere (in this example, I put it in B6). Then for the corresponding max in A you can use the formula MAX(ARRAYFORMULA(IF(B2:B4 = $B$6,A2:A4))).






            share|improve this answer








            New contributor




            dcolazin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$



            Suppose you have data in the columns A, B from row 2 to 4. Put MAX(B2:B4) somewhere (in this example, I put it in B6). Then for the corresponding max in A you can use the formula MAX(ARRAYFORMULA(IF(B2:B4 = $B$6,A2:A4))).







            share|improve this answer








            New contributor




            dcolazin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.









            share|improve this answer



            share|improve this answer






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            answered 2 days ago









            dcolazindcolazin

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            • $begingroup$
              That works! Also, see the method I figured out in my separate answer.
              $endgroup$
              – adriandahlin
              2 hours ago
















            • $begingroup$
              That works! Also, see the method I figured out in my separate answer.
              $endgroup$
              – adriandahlin
              2 hours ago















            $begingroup$
            That works! Also, see the method I figured out in my separate answer.
            $endgroup$
            – adriandahlin
            2 hours ago




            $begingroup$
            That works! Also, see the method I figured out in my separate answer.
            $endgroup$
            – adriandahlin
            2 hours ago











            0












            $begingroup$

            I figured this out using the query function and referencing a specific cell.



            First, as @dcolazin suggests, you put the max of column B in a cell (I chose B1):



            =max(B2:B10)


            Then you do this in cell A1 (notice the "&&" to reference a cell within your SQL query):



            =query(A2:B10,"select max(A) where B >= "&B1&"")





            share|improve this answer








            New contributor




            adriandahlin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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            $endgroup$

















              0












              $begingroup$

              I figured this out using the query function and referencing a specific cell.



              First, as @dcolazin suggests, you put the max of column B in a cell (I chose B1):



              =max(B2:B10)


              Then you do this in cell A1 (notice the "&&" to reference a cell within your SQL query):



              =query(A2:B10,"select max(A) where B >= "&B1&"")





              share|improve this answer








              New contributor




              adriandahlin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.






              $endgroup$















                0












                0








                0





                $begingroup$

                I figured this out using the query function and referencing a specific cell.



                First, as @dcolazin suggests, you put the max of column B in a cell (I chose B1):



                =max(B2:B10)


                Then you do this in cell A1 (notice the "&&" to reference a cell within your SQL query):



                =query(A2:B10,"select max(A) where B >= "&B1&"")





                share|improve this answer








                New contributor




                adriandahlin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                $endgroup$



                I figured this out using the query function and referencing a specific cell.



                First, as @dcolazin suggests, you put the max of column B in a cell (I chose B1):



                =max(B2:B10)


                Then you do this in cell A1 (notice the "&&" to reference a cell within your SQL query):



                =query(A2:B10,"select max(A) where B >= "&B1&"")






                share|improve this answer








                New contributor




                adriandahlin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                share|improve this answer



                share|improve this answer






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                answered 2 hours ago









                adriandahlinadriandahlin

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                32




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