Hfrxdjt

Continuing from the comments above:

Using is_integer():

Example from the docs:

>>> 1.5.is_integer()
False
>>> 1.0.is_integer()
True
>>> 1.4142135623730951.is_integer()
False

Hence:

s = [1.5, 1.0, 2.5, 3.54, 1.0]

print([int(x) if x.is_integer() else x for x in s])

OUTPUT:

[1.5, 1, 2.5, 3.54, 1]

Wrapped in a function:

def func(s):
 return [int(x) if x.is_integer() else x for x in s]

print(func(s))

In case your goal is to convert numbers to a concise string, you could simply use '%g' ("General Format") for formatting:

>>> '%g' % 1.0
'1'
>>> '%g' % 1
'1'
>>> '%g' % 1.5
'1.5'
>>> '%g' % 0.3
'0.3'
>>> '%g' % 0.9999999999
'1'

Python floats are approximations, so something that prints as 1.0 is not necessarily exactly 1.0. If you want to see if something is approximately an integer, use a sufficiently small epsilon value.

EPSILON = 0.0001 # Make this smaller or larger depending on desired accuracy

def func(x):
 if abs(x - round(x)) < EPSILON:
 return round(x)
 else:
 return x

In general, if you're checking whether a float is == to something, that tends to be a code smell, as floating point values are inherently approximate. It's more appropriate in general to check whether a float is near something, within some epsilon range.

Use this function:

def to_int(a):
 if a.is_integer():
 return int(a)
 return a
print(to_int(1.5))
print(to_int(1.0))

Output:

1.5
1

What I used to do in the past in C++ is, lets say you have these variables:

float x = 1.5;
float y = 1.0;

Then you could do something like this:

if(x == (int)x) 
 return 1;
else return 0;

This will return 0 because 1.5 is not equal to 1

if(y == (int)y) 
 return 1;
else return 0;

This will return 1 because 1.0 is equal to 1

Of course your question is about Python and the function is_integer() should work great, I just thought some people might find this useful.

A simple thing you could do is use the modulo operator:

if (myFloat % 1 == 0) // Number is an int
else // numer is not an int

(Note: Not real code (although compilable with some languages)!)

EDIT:
Thanks to "popular demand" here's some Python code (untested):

if myFloat % 1 = 0:
 # Is an integer
 return int(myFloat)
else:
 # Is not an integer
 return myFloat

Again, the code is untested, but I think it should work (not too familiar w/ Python, tbh)