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Flattening the sub-lists

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Flattening the sub-lists



Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Remove elements at certain positions from all sub-lists?How to group lists that own one common element?Searching linked lists that contain lists?Partition list into a given number of sub-listsHow to plot specific listsList of (sub-)lists - query sub-lists by names?How to efficiently Flatten nested lists while preserving select levels?Flattening large list of listsDeleting sub-list that contains duplicatesSpeed up Flatten[] of a large nested list










2












$begingroup$


Is there a way to flatten the sub-lists within a list?



Transform



1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


Into



1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


I know I can do



Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


I am wondering whether there are some dedicated functions for such sub-list flattening?










share|improve this question











$endgroup$







  • 3




    $begingroup$
    try Flatten[list,1]
    $endgroup$
    – J42161217
    6 hours ago










  • $begingroup$
    One can also consider using Join @@ yourlist.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    3 hours ago















2












$begingroup$


Is there a way to flatten the sub-lists within a list?



Transform



1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


Into



1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


I know I can do



Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


I am wondering whether there are some dedicated functions for such sub-list flattening?










share|improve this question











$endgroup$







  • 3




    $begingroup$
    try Flatten[list,1]
    $endgroup$
    – J42161217
    6 hours ago










  • $begingroup$
    One can also consider using Join @@ yourlist.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    3 hours ago













2












2








2





$begingroup$


Is there a way to flatten the sub-lists within a list?



Transform



1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


Into



1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


I know I can do



Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


I am wondering whether there are some dedicated functions for such sub-list flattening?










share|improve this question











$endgroup$




Is there a way to flatten the sub-lists within a list?



Transform



1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


Into



1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


I know I can do



Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x


I am wondering whether there are some dedicated functions for such sub-list flattening?







list-manipulation






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 6 hours ago









m0nhawk

2,92711532




2,92711532










asked 6 hours ago









bakerbaker

463




463







  • 3




    $begingroup$
    try Flatten[list,1]
    $endgroup$
    – J42161217
    6 hours ago










  • $begingroup$
    One can also consider using Join @@ yourlist.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    3 hours ago












  • 3




    $begingroup$
    try Flatten[list,1]
    $endgroup$
    – J42161217
    6 hours ago










  • $begingroup$
    One can also consider using Join @@ yourlist.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    3 hours ago







3




3




$begingroup$
try Flatten[list,1]
$endgroup$
– J42161217
6 hours ago




$begingroup$
try Flatten[list,1]
$endgroup$
– J42161217
6 hours ago












$begingroup$
One can also consider using Join @@ yourlist.
$endgroup$
– Αλέξανδρος Ζεγγ
3 hours ago




$begingroup$
One can also consider using Join @@ yourlist.
$endgroup$
– Αλέξανδρος Ζεγγ
3 hours ago










2 Answers
2






active

oldest

votes


















7












$begingroup$

You are doing redundant step with /@, Flatten can make this directly:



Flatten[1, x, 2, x, 3, x, 4, x, 5, 
x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8,
x, 9, x, 10, x *)





share|improve this answer









$endgroup$




















    0












    $begingroup$

    Yes, there is a built-in function for what you want to do.



    data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
    Catenate @ data



    1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x





    share









    $endgroup$













      Your Answer








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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      7












      $begingroup$

      You are doing redundant step with /@, Flatten can make this directly:



      Flatten[1, x, 2, x, 3, x, 4, x, 5, 
      x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
      (* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8,
      x, 9, x, 10, x *)





      share|improve this answer









      $endgroup$

















        7












        $begingroup$

        You are doing redundant step with /@, Flatten can make this directly:



        Flatten[1, x, 2, x, 3, x, 4, x, 5, 
        x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
        (* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8,
        x, 9, x, 10, x *)





        share|improve this answer









        $endgroup$















          7












          7








          7





          $begingroup$

          You are doing redundant step with /@, Flatten can make this directly:



          Flatten[1, x, 2, x, 3, x, 4, x, 5, 
          x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
          (* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8,
          x, 9, x, 10, x *)





          share|improve this answer









          $endgroup$



          You are doing redundant step with /@, Flatten can make this directly:



          Flatten[1, x, 2, x, 3, x, 4, x, 5, 
          x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
          (* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8,
          x, 9, x, 10, x *)






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 5 hours ago









          m0nhawkm0nhawk

          2,92711532




          2,92711532





















              0












              $begingroup$

              Yes, there is a built-in function for what you want to do.



              data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
              Catenate @ data



              1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x





              share









              $endgroup$

















                0












                $begingroup$

                Yes, there is a built-in function for what you want to do.



                data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
                Catenate @ data



                1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x





                share









                $endgroup$















                  0












                  0








                  0





                  $begingroup$

                  Yes, there is a built-in function for what you want to do.



                  data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
                  Catenate @ data



                  1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x





                  share









                  $endgroup$



                  Yes, there is a built-in function for what you want to do.



                  data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
                  Catenate @ data



                  1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x






                  share











                  share


                  share










                  answered 7 mins ago









                  m_goldbergm_goldberg

                  89.1k873200




                  89.1k873200



























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