C++ copy constructor called at returnWhen to use virtual destructors?In which situations is the C++ copy constructor called?What are the differences between a pointer variable and a reference variable in C++?Why don't C++ compilers define operator== and operator!=?What is the lifetime of a static variable in a C++ function?Can I call a constructor from another constructor (do constructor chaining) in C++?Inheriting constructorsHow can I profile C++ code running on Linux?The Definitive C++ Book Guide and ListWhen to use virtual destructors?What is the “-->” operator in C++?What is the copy-and-swap idiom?
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C++ copy constructor called at return
When to use virtual destructors?In which situations is the C++ copy constructor called?What are the differences between a pointer variable and a reference variable in C++?Why don't C++ compilers define operator== and operator!=?What is the lifetime of a static variable in a C++ function?Can I call a constructor from another constructor (do constructor chaining) in C++?Inheriting constructorsHow can I profile C++ code running on Linux?The Definitive C++ Book Guide and ListWhen to use virtual destructors?What is the “-->” operator in C++?What is the copy-and-swap idiom?
error: use of deleted function 'A::A(const A&)'
return tmp;
^~~
Why is the copy constructor called only when there is a virtual destructor in A? How to avoid this?
struct B ;
struct A
std::unique_ptr<B> x;
virtual ~A() = default;
;
A f()
A tmp;
return tmp;
c++
New contributor
Sobuch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
error: use of deleted function 'A::A(const A&)'
return tmp;
^~~
Why is the copy constructor called only when there is a virtual destructor in A? How to avoid this?
struct B ;
struct A
std::unique_ptr<B> x;
virtual ~A() = default;
;
A f()
A tmp;
return tmp;
c++
New contributor
Sobuch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
see: In which situations is the C++ copy constructor called?
– kmdreko
1 hour ago
3
C++ handles objects different than C#/Java. When an instance goes out of scope (tmphere) its destructor must be called. Therefore, when youreturn tmpthen you're asking it to make a copy oftmpto be return to whomever calls the function. Once copied,tmpwill be destroyed and its copy will be available for use.
– Everyone
1 hour ago
add a comment |
error: use of deleted function 'A::A(const A&)'
return tmp;
^~~
Why is the copy constructor called only when there is a virtual destructor in A? How to avoid this?
struct B ;
struct A
std::unique_ptr<B> x;
virtual ~A() = default;
;
A f()
A tmp;
return tmp;
c++
New contributor
Sobuch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
error: use of deleted function 'A::A(const A&)'
return tmp;
^~~
Why is the copy constructor called only when there is a virtual destructor in A? How to avoid this?
struct B ;
struct A
std::unique_ptr<B> x;
virtual ~A() = default;
;
A f()
A tmp;
return tmp;
c++
c++
New contributor
Sobuch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Sobuch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Sobuch
New contributor
Sobuch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
SobuchSobuch
385
385
New contributor
Sobuch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Sobuch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Sobuch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
see: In which situations is the C++ copy constructor called?
– kmdreko
1 hour ago
3
C++ handles objects different than C#/Java. When an instance goes out of scope (tmphere) its destructor must be called. Therefore, when youreturn tmpthen you're asking it to make a copy oftmpto be return to whomever calls the function. Once copied,tmpwill be destroyed and its copy will be available for use.
– Everyone
1 hour ago
add a comment |
see: In which situations is the C++ copy constructor called?
– kmdreko
1 hour ago
3
C++ handles objects different than C#/Java. When an instance goes out of scope (tmphere) its destructor must be called. Therefore, when youreturn tmpthen you're asking it to make a copy oftmpto be return to whomever calls the function. Once copied,tmpwill be destroyed and its copy will be available for use.
– Everyone
1 hour ago
see: In which situations is the C++ copy constructor called?
– kmdreko
1 hour ago
see: In which situations is the C++ copy constructor called?
– kmdreko
1 hour ago
3
3
C++ handles objects different than C#/Java. When an instance goes out of scope (
tmp here) its destructor must be called. Therefore, when you return tmp then you're asking it to make a copy of tmp to be return to whomever calls the function. Once copied, tmp will be destroyed and its copy will be available for use.– Everyone
1 hour ago
C++ handles objects different than C#/Java. When an instance goes out of scope (
tmp here) its destructor must be called. Therefore, when you return tmp then you're asking it to make a copy of tmp to be return to whomever calls the function. Once copied, tmp will be destroyed and its copy will be available for use.– Everyone
1 hour ago
add a comment |
1 Answer
1
active
oldest
votes
virtual ~A() = default; is a user declared destructor. Because of that, A no longer has a move constructor. That means return tmp; can't move tmp and since tmp is not copyable, you get a compiler error.
There are two ways you can fix this. You can add a move constructor like
struct A
std::unique_ptr<B> x;
A() = default; // you have to add this since the move constructor was added
A(A&&) = default; // defaulted move
virtual ~A() = default;
;
or you can create a base class that has the virtual destructor and inherit from that like
struct C
virtual ~C() = default;
;
struct A : C
std::unique_ptr<B> x;
;
5
Better to follow the Rule of Zero/Five. Either add all of (copy ctor, move ctor, copy assignment, move assignment, destructor) or add none of them. In this example, none of them are necessary.
– 0x5453
1 hour ago
1
@0x5453 Unless this is a parent class and the OP wants the derived classes to get destroyed properly. You need a virtual destructor if you have polymorphism.
– NathanOliver
1 hour ago
2
@Tzalumen no delete is required (because that's what the unique pointer does for you), but a virtual destructor is required so that the unique pointer won't have UB.
– eerorika
1 hour ago
3
@Tzalumen If youdeletean object of classXthrough a pointer to a base class ofXand that base class doesn't have a virtual dtor, it's Undefined Behaviour. Regardless of what the destructor does.
– Angew
1 hour ago
3
@Tzalumen If you have polymorphism, you must have a virtual destructor. If you don't the destructor for the derived class won't be called and you have UB.
– NathanOliver
1 hour ago
|
show 23 more comments
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virtual ~A() = default; is a user declared destructor. Because of that, A no longer has a move constructor. That means return tmp; can't move tmp and since tmp is not copyable, you get a compiler error.
There are two ways you can fix this. You can add a move constructor like
struct A
std::unique_ptr<B> x;
A() = default; // you have to add this since the move constructor was added
A(A&&) = default; // defaulted move
virtual ~A() = default;
;
or you can create a base class that has the virtual destructor and inherit from that like
struct C
virtual ~C() = default;
;
struct A : C
std::unique_ptr<B> x;
;
5
Better to follow the Rule of Zero/Five. Either add all of (copy ctor, move ctor, copy assignment, move assignment, destructor) or add none of them. In this example, none of them are necessary.
– 0x5453
1 hour ago
1
@0x5453 Unless this is a parent class and the OP wants the derived classes to get destroyed properly. You need a virtual destructor if you have polymorphism.
– NathanOliver
1 hour ago
2
@Tzalumen no delete is required (because that's what the unique pointer does for you), but a virtual destructor is required so that the unique pointer won't have UB.
– eerorika
1 hour ago
3
@Tzalumen If youdeletean object of classXthrough a pointer to a base class ofXand that base class doesn't have a virtual dtor, it's Undefined Behaviour. Regardless of what the destructor does.
– Angew
1 hour ago
3
@Tzalumen If you have polymorphism, you must have a virtual destructor. If you don't the destructor for the derived class won't be called and you have UB.
– NathanOliver
1 hour ago
|
show 23 more comments
virtual ~A() = default; is a user declared destructor. Because of that, A no longer has a move constructor. That means return tmp; can't move tmp and since tmp is not copyable, you get a compiler error.
There are two ways you can fix this. You can add a move constructor like
struct A
std::unique_ptr<B> x;
A() = default; // you have to add this since the move constructor was added
A(A&&) = default; // defaulted move
virtual ~A() = default;
;
or you can create a base class that has the virtual destructor and inherit from that like
struct C
virtual ~C() = default;
;
struct A : C
std::unique_ptr<B> x;
;
5
Better to follow the Rule of Zero/Five. Either add all of (copy ctor, move ctor, copy assignment, move assignment, destructor) or add none of them. In this example, none of them are necessary.
– 0x5453
1 hour ago
1
@0x5453 Unless this is a parent class and the OP wants the derived classes to get destroyed properly. You need a virtual destructor if you have polymorphism.
– NathanOliver
1 hour ago
2
@Tzalumen no delete is required (because that's what the unique pointer does for you), but a virtual destructor is required so that the unique pointer won't have UB.
– eerorika
1 hour ago
3
@Tzalumen If youdeletean object of classXthrough a pointer to a base class ofXand that base class doesn't have a virtual dtor, it's Undefined Behaviour. Regardless of what the destructor does.
– Angew
1 hour ago
3
@Tzalumen If you have polymorphism, you must have a virtual destructor. If you don't the destructor for the derived class won't be called and you have UB.
– NathanOliver
1 hour ago
|
show 23 more comments
virtual ~A() = default; is a user declared destructor. Because of that, A no longer has a move constructor. That means return tmp; can't move tmp and since tmp is not copyable, you get a compiler error.
There are two ways you can fix this. You can add a move constructor like
struct A
std::unique_ptr<B> x;
A() = default; // you have to add this since the move constructor was added
A(A&&) = default; // defaulted move
virtual ~A() = default;
;
or you can create a base class that has the virtual destructor and inherit from that like
struct C
virtual ~C() = default;
;
struct A : C
std::unique_ptr<B> x;
;
virtual ~A() = default; is a user declared destructor. Because of that, A no longer has a move constructor. That means return tmp; can't move tmp and since tmp is not copyable, you get a compiler error.
There are two ways you can fix this. You can add a move constructor like
struct A
std::unique_ptr<B> x;
A() = default; // you have to add this since the move constructor was added
A(A&&) = default; // defaulted move
virtual ~A() = default;
;
or you can create a base class that has the virtual destructor and inherit from that like
struct C
virtual ~C() = default;
;
struct A : C
std::unique_ptr<B> x;
;
edited 1 hour ago
answered 1 hour ago
NathanOliverNathanOliver
96k16136209
96k16136209
5
Better to follow the Rule of Zero/Five. Either add all of (copy ctor, move ctor, copy assignment, move assignment, destructor) or add none of them. In this example, none of them are necessary.
– 0x5453
1 hour ago
1
@0x5453 Unless this is a parent class and the OP wants the derived classes to get destroyed properly. You need a virtual destructor if you have polymorphism.
– NathanOliver
1 hour ago
2
@Tzalumen no delete is required (because that's what the unique pointer does for you), but a virtual destructor is required so that the unique pointer won't have UB.
– eerorika
1 hour ago
3
@Tzalumen If youdeletean object of classXthrough a pointer to a base class ofXand that base class doesn't have a virtual dtor, it's Undefined Behaviour. Regardless of what the destructor does.
– Angew
1 hour ago
3
@Tzalumen If you have polymorphism, you must have a virtual destructor. If you don't the destructor for the derived class won't be called and you have UB.
– NathanOliver
1 hour ago
|
show 23 more comments
5
Better to follow the Rule of Zero/Five. Either add all of (copy ctor, move ctor, copy assignment, move assignment, destructor) or add none of them. In this example, none of them are necessary.
– 0x5453
1 hour ago
1
@0x5453 Unless this is a parent class and the OP wants the derived classes to get destroyed properly. You need a virtual destructor if you have polymorphism.
– NathanOliver
1 hour ago
2
@Tzalumen no delete is required (because that's what the unique pointer does for you), but a virtual destructor is required so that the unique pointer won't have UB.
– eerorika
1 hour ago
3
@Tzalumen If youdeletean object of classXthrough a pointer to a base class ofXand that base class doesn't have a virtual dtor, it's Undefined Behaviour. Regardless of what the destructor does.
– Angew
1 hour ago
3
@Tzalumen If you have polymorphism, you must have a virtual destructor. If you don't the destructor for the derived class won't be called and you have UB.
– NathanOliver
1 hour ago
5
5
Better to follow the Rule of Zero/Five. Either add all of (copy ctor, move ctor, copy assignment, move assignment, destructor) or add none of them. In this example, none of them are necessary.
– 0x5453
1 hour ago
Better to follow the Rule of Zero/Five. Either add all of (copy ctor, move ctor, copy assignment, move assignment, destructor) or add none of them. In this example, none of them are necessary.
– 0x5453
1 hour ago
1
1
@0x5453 Unless this is a parent class and the OP wants the derived classes to get destroyed properly. You need a virtual destructor if you have polymorphism.
– NathanOliver
1 hour ago
@0x5453 Unless this is a parent class and the OP wants the derived classes to get destroyed properly. You need a virtual destructor if you have polymorphism.
– NathanOliver
1 hour ago
2
2
@Tzalumen no delete is required (because that's what the unique pointer does for you), but a virtual destructor is required so that the unique pointer won't have UB.
– eerorika
1 hour ago
@Tzalumen no delete is required (because that's what the unique pointer does for you), but a virtual destructor is required so that the unique pointer won't have UB.
– eerorika
1 hour ago
3
3
@Tzalumen If you
delete an object of class X through a pointer to a base class of X and that base class doesn't have a virtual dtor, it's Undefined Behaviour. Regardless of what the destructor does.– Angew
1 hour ago
@Tzalumen If you
delete an object of class X through a pointer to a base class of X and that base class doesn't have a virtual dtor, it's Undefined Behaviour. Regardless of what the destructor does.– Angew
1 hour ago
3
3
@Tzalumen If you have polymorphism, you must have a virtual destructor. If you don't the destructor for the derived class won't be called and you have UB.
– NathanOliver
1 hour ago
@Tzalumen If you have polymorphism, you must have a virtual destructor. If you don't the destructor for the derived class won't be called and you have UB.
– NathanOliver
1 hour ago
|
show 23 more comments
Sobuch is a new contributor. Be nice, and check out our Code of Conduct.
Sobuch is a new contributor. Be nice, and check out our Code of Conduct.
Sobuch is a new contributor. Be nice, and check out our Code of Conduct.
Sobuch is a new contributor. Be nice, and check out our Code of Conduct.
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see: In which situations is the C++ copy constructor called?
– kmdreko
1 hour ago
3
C++ handles objects different than C#/Java. When an instance goes out of scope (
tmphere) its destructor must be called. Therefore, when youreturn tmpthen you're asking it to make a copy oftmpto be return to whomever calls the function. Once copied,tmpwill be destroyed and its copy will be available for use.– Everyone
1 hour ago